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2 years ago

How many inches did the height of the plant increase between weeks 3 and 4

Mathematics

2 answers:

Allisa [31]2 years ago

6 0

It increased a total of 4 inches.

fredd [130]2 years ago

3 0

The plant increased a total of 4 inches. Week 3 the plant increased 8 inches and week 4 the plant was 12 in, now subtract 12-8= 4

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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

A bag contains 5 black marbles, 7 blue marbles, 3 green marbles, 4 red marbles, and 1 white marble. A marble is selected and the

schepotkina [342]

Answer:

2/25

Step-by-step explanation:

It will be 20/400 + 12/400

=2/25

5 0

2 years ago

The expression sin x (cos x cot x - sin x) simplifies to?

nikdorinn [45]

◆ Trigonometric Identities ◆

Hey !!

Check the attachment.
Hope it helps you :)

8 0

2 years ago

Read 2 more answers

The relationship between the amount of money x that Cannon Precision Instruments spends on advertising and the company's total s

mafiozo [28]

Answer:

S'(x)=-0.006x2+0.8x+9

Step-by-step explanation:

The rate of change of the sales S(x) with respect to the amount of money spent on advertising x is then the derivative of S(x) with respect to x. What we have to calculate is S'(x).

We know that the derivative of $ax^n$ is $nax^{n-1}$ (where a is a constant), and the derivative of a sum is the sum of the derivatives, so we can calculate the derivative of each term independently: