There is no algebraic way of isolating X unfortunately.
For these equations, you have to solve with numerical approximation.
I suggest Newtons method if you know calculus.
A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:
y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)
In this case we are given that (h,k) is (-5,80) so we have so far:
y=a(x--5)^2+80
y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:
-45=a(0+5)^2+80
-45=25a+80 subtract 80 from both sides
-125=25a divide both sides by 25
-5=a, so now we know the complete vertex form is:
y=-5(x+5)^2+80
The x-intercepts occur when y=0 so:
0=-5(x+5)^2+80 add 5(x+5)^2 to both sides
5(x+5)^2=80 divide both sides by 5
(x+5)^2=16 take the square root of both sides
x+5=±√16 which is
x+5=±4 subtract 5 from both sides
x=-5±4 so the x-intercepts are:
x=-1 and -9
Answer:
x=17
Step-by-step explanation:
This should be for a "kite": AD=DC, AB=BC and ∠A=∠C
8x-27 = 3x+58
5x = 85
x = 17
Answer:
The equivalent ratios are:
16:10
8:5
48:30
Step-by-step explanation:
It is given that the ratios are equivalent ratios. So all the ratios will simplify to the same ratio. We can use this to find the ratios.
given ratio is:
16:10
which simplifies to
8:5
We can observe that the second ratio will be same 8:5
Now,
Hence,
The equivalent ratios are:
16:10
8:5
48:30
