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julsineya [31]
3 years ago
5

(-2x+y=8) minus (5x-y=6)

Mathematics
2 answers:
Elis [28]3 years ago
8 0
-2x+y - (5x-y) = 8-6 <=>

-2x+y-5x+y = 2 <=>

-7x + 2y = 2
Hitman42 [59]3 years ago
6 0

Answer:-7x+2y=2

Step-by-step explanation:

(-2x+y=8)-(5x-y=6)

(-2x+y=8)> this side change since it’s negative

(-2x+y=8) - (-5x+y=-6)

-7x+2y=2

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Given the domain {-4, 0, 5}, what is the range for the relation 12x, + 6y = 24?
Alinara [238K]

↣ Substitute all domains in the equation for the ranges.

12x+6y=24    

2x+y=4     ↣ Divide the whole equation by 6.

↣ Substitute x = -4 in the equation.

2(-4)+y=4\\-8+y=4\\y=4+8\\y=12

Our range is 12 when x = -4. In the choice there is only one choice that has range value as 12. Therefore, the answer is B.

↣ <em>If you want me to solve for all ranges then you can reply under this. Since there is only one choice that has 12 as range value, I decide not to continue. So If you want me to solve for all ranges then feel free to reply under this. ↣</em>

7 0
3 years ago
Write the equation in Slope - intercept form by solving for y. 2x+3y=12
Gennadij [26K]

y=-2/3x+4 i hope this helps!

7 0
3 years ago
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Solve the compound inequality<br> 3t-8/5 and 4-t&lt;-7
Sav [38]

Answer: -2.8

Step-by-step explanation:

3t-(8/5) * 4-t < -7

(15t-8)/5 * 4-t < -7

((15t-8)(4-t))/5 < -7

(15t^2)-28t-32< -7

(15t^2)-28t-32-7< 0

(15t^2)-28t-39< 0

Using the quadratic/almighty formula

t= (-b +- ((b^2)-4ac)^(1/2)/2a)

a=15, b=-28, c=-39

t= (-(28) +- (((-28)^2)-4(15)(-39))^(1/2))/2(15))

t= -2.8 or t= 0.9

Since

t<0, then t= -2.8

8 0
3 years ago
Find the value of N please!!
V125BC [204]

Answer:

n = - 5

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

\frac{a^{m} }{a^{n} } ⇔ a^{(m-n)}

Consider the left side

\frac{y^4.y^{n} }{y^2}

= \frac{y^{4+n} }{y^2}

= y^{4+n-2}

= y^{2+n}, then

y^{2+n} = y^{-3}

Since the bases on both sides are the same, equate the exponents

2 + n = - 3 ( subtract 2 from both sides )

n = - 5

6 0
3 years ago
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Help me!!!<br> im stuck here<br> if you could help me answer this then please do!!!1
kondaur [170]

Answer:

123.4

Step-by-step explanation:

So I added all of the numbers then divide by how many numbers there was so I divided by 5 because I also counted the x as part of it.

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3 years ago
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