↣ Substitute all domains in the equation for the ranges.
↣ Divide the whole equation by 6.
↣ Substitute x = -4 in the equation.
Our range is 12 when x = -4. In the choice there is only one choice that has range value as 12. Therefore, the answer is B.
↣ <em>If you want me to solve for all ranges then you can reply under this. Since there is only one choice that has 12 as range value, I decide not to continue. So If you want me to solve for all ranges then feel free to reply under this. ↣</em>
Answer: -2.8
Step-by-step explanation:
3t-(8/5) * 4-t < -7
(15t-8)/5 * 4-t < -7
((15t-8)(4-t))/5 < -7
(15t^2)-28t-32< -7
(15t^2)-28t-32-7< 0
(15t^2)-28t-39< 0
Using the quadratic/almighty formula
t= (-b +- ((b^2)-4ac)^(1/2)/2a)
a=15, b=-28, c=-39
t= (-(28) +- (((-28)^2)-4(15)(-39))^(1/2))/2(15))
t= -2.8 or t= 0.9
Since
t<0, then t= -2.8
Answer:
n = - 5
Step-by-step explanation:
Using the rules of exponents
× 
⇔ 
⇔ 
Consider the left side
= 
= 
= 
, then
= 
Since the bases on both sides are the same, equate the exponents
2 + n = - 3 ( subtract 2 from both sides )
n = - 5
Answer:
123.4
Step-by-step explanation:
So I added all of the numbers then divide by how many numbers there was so I divided by 5 because I also counted the x as part of it.
