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solmaris [256]
4 years ago
12

Write 5 3/10 as a improper fraction

Mathematics
2 answers:
Alexus [3.1K]4 years ago
8 0
5 3/10 
5(10) = 50 + 3 = 53 - numerator, denominator stays the same
53/10 - answer 
nikitadnepr [17]4 years ago
5 0
5 3/10 5 (10)=50+3=53-numerator Denominator stay the same 53/10-answer
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The football team has a total of 350 jersey there are 150 medium-sized-jersey. Percent of jerseys are medium-sized-jerseys
liubo4ka [24]

Answer: 525

Step-by-step explanation:

if your looking for 150 percent of 350, the answer is 525 because....

150 x 350/ 100 =525

3 0
3 years ago
P=-3w+9 <br><br><br><br>tell me the steps I already have the steps
anastassius [24]
You're solving for w for I assume.

P= -3w+9, put -3w on the left side and P on the right side.
3w= -P+9, divide both sides by 3.
w= -P+9 over 3.
w= -P over 3 plus  9 over 3.
(Final Answer):
w= -p over 3 plus 3.

Hope this helps. 
4 0
3 years ago
The weights of cars passing over a bridge has a mean of 3550 lb and a standard deviation of 870 lb. Assume that the weights of t
elena-s [515]

Step-by-step explanation:

Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs.  So choose appropriate answer accordingly (near the end)

Using the usual notations and formulas,

mean, mu = 3550

standard deviation, sigma = 870

Observed value, X = 3000

We calculate

Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839

Probability of weight below 3000 lbs

= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334

Answer:

Probability that a car randomly selected is less than 3000

= P(X<3000) = 0.2636 (to 4 decimals)

Probability that a car randomly selected is greater than 3000

= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)

5 0
3 years ago
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3x-6=-3
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They offer two different vacation packages

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3 years ago
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