Fun. I prefer Oxymetazoline.
For the control group we have a headache probability of
c = 368/1671 = .220
For the experimental group we have a headache probability of
e = 494/2013 = .245
The observed difference is
d = e - c = .025
The variance of the difference is
s² = c(1-c)/n₁ + e(1-e)/n₂
so the standard deviation is
We get a t statistic on the difference of
t = d/s = .025/.0139 = 1.79
We're interested in the one sided test, P(d > 0). We have enough dfs to assume normality. We look up in the standard normal table
P(z < 1.79) = .96327
so
p = P(z > 1.79) = 1 - .96327 = 0.037 = 3.7%
Answer: That's less that 10% so we have evidence to conclude that headaches are significantly greater in the experimental group.
Answer:
18km
40.5km
Step-by-step explanation:
Let b = journey by bus
c = journey by bicycle
d = total journey
c = (2/3 x d) x 2/3
divide both sides by 2/s
c(3/2) = (2/3)d
c + 9km = 2/3d
c + 9km = 3/2 c
collect like terms and solve for c
3/2c - c = 9km
1/2c = 9km
c = 18km
2. IF cycling (18km) and walking (9km) make up 2/3 of the journey, 2/3 of the journey is 27km
2/3d = 27km
divide both sides by 3/2 to find d
d = 40.50 km
The answer is A,
Your farthest x value is -2
Answer:
Judy is 16 years old
Step-by-step explanation:
J = Judy's age
A = Adams age
J = 2A
Six years ago (subtract 6 from the ages)
(J-6) = 5*(A-6)
Distribute
J-6 = 5A - 30
Substitute J = 2A
2A -6 = 5A -30
Subtract 2A from both sides
2A-2A -6 = 5A-2A -30
-6 = 3A -30
Add 30 to each side
-6+30 = 3A-30+30
24 = 3A
Divide by 3
24/3 = 3A/3
8 = A
Adam is 8 years old now
We need to find Judy's age
J = 2A
J = 2*8
J = 16
Judy is 16 years old
Answer:
3 7/10 = 37/10
Step-by-step explanation:
