Answer:
The pairs of integer having two real solution for
are




Step-by-step explanation:
Given

Now we will solve the equation by putting all the 6 pairs so we get the following
for 
for 
for 
for 
for 
for 
The above all are Quadratic equations inn general form 
where we have a,b and c constant values
So for a real Solution we must have

for
we have
which is less than 0 ∴ not a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is equal to 0 ∴ a real solution.
for
we have
which is less than 0 ∴ not a real solution.
since LM=LN there values are same which is given as 5.5 cm and MN =7cm
now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!
Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.
<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>
C, if there is an odd number of negatives it is negative, if there is an even number it is positive
Answer:
-27
Step-by-step explanation: