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Jet001 [13]
3 years ago
13

Name a possible value for w that is a solution to w > 30, but is not a solution to w < 50. Thank you in advance for the he

lp.
Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

i dont know

Step-by-step explanation:E

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What does the 2 represent in the equation 2÷4=1/2
Katyanochek1 [597]

Answer:

  the dividend of the left expression, and the denominator of the right expression

Step-by-step explanation:

"2" appears in two places in the equation.

On the left, it is the number being divided, the dividend.

On the right, it is the denominator of the fraction.

6 0
3 years ago
Use the quadratic formula to solve for x.<br> 3x2 + 2x - 6 = 0
Daniel [21]

Answer:

x = 1/3 (sqrt(19) - 1) or x = (1/3 (-1 - sqrt(19)))

Step-by-step explanation:

Solve for x over the real numbers:

3 x^2 + 2 x - 6 = 0

Using the quadratic formula, solve for x.

x = (-2 ± sqrt(2^2 - 4×3 (-6)))/(2×3) = (-2 ± sqrt(4 + 72))/6 = (-2 ± sqrt(76))/6:

x = (-2 + sqrt(76))/6 or x = (-2 - sqrt(76))/6

Simplify radicals.

sqrt(76) = sqrt(4×19) = sqrt(2^2×19) = 2sqrt(19):

x = (2 sqrt(19) - 2)/6 or x = (-2 sqrt(19) - 2)/6

Factor the greatest common divisor (gcd) of -2, 2 sqrt(19) and 6 from -2 + 2 sqrt(19).

Factor 2 from -2 + 2 sqrt(19) giving 2 (sqrt(19) - 1):

x = 1/6(2 (sqrt(19) - 1)) or x = (-2 sqrt(19) - 2)/6

In (2 (sqrt(19) - 1))/6, divide 6 in the denominator by 2 in the numerator.

(2 (sqrt(19) - 1))/6 = (2 (sqrt(19) - 1))/(2×3) = (sqrt(19) - 1)/3:

x = (1/3 (sqrt(19) - 1)) or x = (-2 sqrt(19) - 2)/6

Factor the greatest common divisor (gcd) of -2, -2 sqrt(19) and 6 from -2 - 2 sqrt(19).

Factor 2 from -2 - 2 sqrt(19) giving 2 (-sqrt(19) - 1):

x = 1/3 (sqrt(19) - 1) or x = 1/6(2 (-1 - sqrt(19)))

In (2 (-sqrt(19) - 1))/6, divide 6 in the denominator by 2 in the numerator.

(2 (-sqrt(19) - 1))/6 = (2 (-sqrt(19) - 1))/(2×3) = (-sqrt(19) - 1)/3:

Answer:  x = 1/3 (sqrt(19) - 1) or x = (1/3 (-1 - sqrt(19)))

4 0
2 years ago
Find the volume of the sphere. Round your answer to the nearest tenth.use 3.14 for pi. Radius of 2.6 meters
LenaWriter [7]
Volume of a sphere = 4/3(3.14)(2.6)^3

Raise 2.6 to the third power and substitute it in the equation

Multiply that number by 3.14

Whatever your answer is, times it by 4

Then divide that answer by 3

Hope this helps !
4 0
3 years ago
Read 2 more answers
Questions are in the pictures
Elan Coil [88]

The values of h and r to maximize the volume are r = 4 and h = 2

<h3>The formula for h in terms of r</h3>

From the question, we have the following equation

2r + 2h = 12

Divide through by 2

r + h = 6

Subtract r from both sides of the equation

h = 6 - r

Hence, the formula for h in terms of r is h = 6 - r

<h3>Formulate a function V(r)</h3>

The volume of a cylinder is

V = πr²h

Substitute h = 6 - r in the above equation

V = πr²(6 - r)

Hence, the function V(r) is V = πr²(6 - r)

<h3>The single critical point</h3>

V = πr²(6 - r)

Expand

V = 6πr² - πr³

Integrate

V' = 12πr - 3πr²

Set to 0

12πr - 3πr² = 0

Divide through by 3π

4r - r² = 0

Factor out r

r(4 - r) = 0

Divide through by 4

4 - r = 0

Solve for r

r = 4

Hence, the single critical point on the interval [0. 6] is r = 4

<h3>Prove that the critical point is a global maximum</h3>

We have:

V = πr²(6 - r)

and

V' = 12πr - 3πr²

Determine the second derivative

V'' = 12π - 6πr

Set r = 4

V'' = 12π - 6π* 4

Evaluate the product

V'' = 12π - 24π

Evaluate the difference

V'' = -12π

Because V'' is negative, then the single critical point is a global maximum

<h3>The values of h and r to maximize the volume</h3>

We have

r = 4  and h = 6 - r

Substitute r = 4  in h = 6 - r

h = 6 - 4

Evaluate

h = 2

Hence, the values of h and r to maximize the volume are r = 4 and h = 2

Read more about maximizing volumes at:

brainly.com/question/1869299

#SPJ1

7 0
2 years ago
What are the roots of the equation x²+2x+17=0 in simplest a+bi form?​
vovikov84 [41]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required roots of given equation are ~

  • \boxed{ \boxed{ - 1 + 4i} \:  \: and \:  \:  \boxed{ - 1 - 4i}}

The solution is in attachment ~

8 0
2 years ago
Read 2 more answers
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