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Veronika [31]
3 years ago
9

Please simplify will give brainliyest

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

   

\displaystyle\bf\\-\sqrt{m^4n^7}=\\\\=-\sqrt{m^{2\times2}\times n^{3\times2+1}}=\\\\=-\sqrt{m^{2\times2}\times n^{3\times2}\times n}}=\\\\=-\sqrt{\Big(m^2\Big)^2\times \Big(n^3\Big)^2\times n}}=\\\\=-\sqrt{\Big(m^2\times n^3\Big)^2\times n}}=\\\\=\boxed{\bf-m^2n^3\sqrt{n}}

 

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