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Lina20 [59]
3 years ago
12

Explain a graded potential.

Biology
1 answer:
Talja [164]3 years ago
7 0

Explanation:

Neurons communicate by changes in electrical properties of the plasma membrane that move from one cell to another. The architecture of the neuron aids the spread of these electrical signals called nerve impulses. A potential difference exists across every cell’s plasma membrane. The side of the membrane exposed to the cytoplasm is the negative pole, and the side exposed to the extracellular fluid is the positive pole. This potential difference is called the membrane potential.

If the plasma membrane is depolarized (moved toward a polarity above that of the resting potential) slightly, an oscilloscope will show a small upward deflection of the line that soon decays back to the resting membrane potential. These small changes in membrane potential are called graded potentials because their amplitudes depend on the strength of the stimulus. Graded potentials can be either depolarizing or hyperpolarizing and can add together to amplify or reduce their effects. The ability of graded potentials to combine is called summation. The level of depolarization needed to produce an action potential is called the threshold.

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A person measures his or her heart rate by counting the number of beats in 30s. If 40±1 beats are counted in 30.0±0.5s, what is
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Heart rate=80 beats per minute

Uncertainty=3 beats per minute

Explanation:

We are given that a person measures heart beat by counting the number of beats in 30 s.

If number of beats=40\pm 1

Time=30.0\pm 0.5

We have to find the heart rate and its uncertainty in beats per minute

Maximum number of beats=40+1=41

Minimum time=30.0-0.5=29.5 s

Because when heart beat increases then time reduces.

We know that 1 minute =60 seconds

Therefore, time =\frac{29.5}{60}=0.492 minutes

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Average time=30 seconds=\frac{30}{60}=0.5 minutes

Heart rate =\frac{number\;of\;beats}{time}

Heart  rate =\frac{40}{0.5}=80 beats per minute

Maximum heart rate=\frac{41}{0.492}=83.33 beats per minute

When minimum number of beats=40-1=39

Maximum time=30.0+0.5=30.5 seconds

Because when heart beat slow then it takes more times

Time=\frac{30.5}{60}=0.508 minutes

Minimum heart rate=\frac{39}{0.508}=76.77 beats per minute

Uncertainty when heart rate is maximum

Uncertainty=83.33-80=3.33 beats per minute

Uncertainty when heart rate is minimum

Uncertainty=80-76.77=3.23 beats per minute

Average uncertainty=\frac{3.33+3.23}{2}

Average uncertainty=3.28 \approx 3beats per minute

Hence, heart rate=80 beats per minute

Uncertainty=3 beats per minute

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