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anygoal [31]
3 years ago
9

Rank the following in terms of increasing momentum:

Physics
2 answers:
Romashka [77]3 years ago
8 0

Based on increasing momentum, the given equations are ranked as following,

1. A 1200 kg car going 15 m/s with momentum 18000  kgm/s.

2. A 15 kg meteor going at the speed of 1000 m/s with momentum 15000 kgm/s.

3. A 100 kg person running at 5 m/s with momentum 500 kgm/s.

4. A 10,000 kg train car at rest with zero momentum.

<u>Explanation:</u>

Momentum is the mass in motion i.e. an object is said to have momentum when it is in motion. The momentum of the object depends upon the mass and the velocity of the object. It is vector quantity since it has both direction and magnitude. The momentum can be evaluated using the formula,

\vec{p}=m \times \vec{v}

where \vec{p} is the momentum,m is the mass and \vec{v} is the velocity of the object

Momentum of given cases,

A) A train car at rest: The momentum of an object at rest is always 0.

B) A 100kg person running at 5 m/s: \vec{p}=m \times \vec{v}=100\ \mathrm{kg} \times 5\ \mathrm{m} / \mathrm{s}=500\ \mathrm{kgm} / \mathrm{s}

Therefore, momentum of the person is 500 kgm/s.

C) A 1200kg car going at 15m/s: \vec{p}=m \times \vec{v}=1200\ \mathrm{kg} \times 15 \frac{\mathrm{m}}{\mathrm{s}}=18000\ \mathrm{kgm} / \mathrm{s}  

Therefore, momentum of the person is 18000 kgm/s.

D) A 15 kg meteor going at the speed of 1000m/s:

\vec{p}=m \times \vec{v}^=15\ \mathrm{kg} \times 1000\ \mathrm{m} / \mathrm{s} =15000\ \mathrm{kgm} / \mathrm{s}

Therefore, momentum of the meteor is 15000 kgm/s.

professor190 [17]3 years ago
5 0
It’s b because if you’re running at 5 miles per second being a 100kg weight is the fastest
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3 years ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

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3 0
2 years ago
A loaf of bread has a mass of 2000g and a volume of 500 cm3. what is the density of the bread
Yuki888 [10]

Answer:

4g/cm^3

Explanation:

density = mass / volume

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7 0
2 years ago
A large, 34.0 kg bell is hung from a wooden beam so it can swing back and forth with negligible friction. The bell's center of m
Lorico [155]

Answer:

length L of the clapper rod for the bell to ring silently = 0.756m

Explanation:

We are given;

Mass of Bell;m_b = 34 kg

Distance of centre of mass from pivot;d = 0.7m

The bells moment of inertia about an axis at the pivot;I = 18 kg.m²

Mass of clapper;m_c = 1.8 kg

Length of slender rod is L

Now, the formula for period of physical pendulum having small amplitude is given as;

T_b = 2π√(I/mgd)

Where;

I is moment of inertia

m is mass

g is acceleration due to gravity = 9.8 m/s²

d is distance from rotation axis to centre of gravity

Plugging in the relevant values and using mass of bell, we have;

T_b = 2π√(18/(34*9.81*0.7)

T_b = 2π√(18/(34*9.81*0.7)

T_b = 1.745 s

Now, the formula for period for a simple pendulum which is essentially what the clapper rod is would be;

T_c = 2π√(L/g)

Now, we want to find length of clapper L.

Thus, let's make it the subject;

L = g(T_c/2π)²

Now, we are told that for the bell to ring silently, T_b = T_c.

Thus, T_c = 1.745 s.

So,

L = 9.8(1.745/2π)²

L = 0.756m

7 0
2 years ago
HELP ASAP!!!
miss Akunina [59]

Write each force in component form:

<em>v </em>₁ : 50 N due east   →   (50 N) <em>i</em>

<em>v</em> ₂ : 80 N at N 45° E   →   (80 N) (cos(45°) <em>i</em> + sin(45°) <em>j</em> ) ≈ (56.5 N) (<em>i</em> + <em>j</em> )

The resultant force is the sum of these two vectors:

<em>r</em> = <em>v </em>₁ + <em>v</em> ₂ ≈ (106.5 N) <em>i</em> + (56.5 N) <em>j</em>

Its magnitude is

|| <em>r</em> || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N

and has direction <em>θ</em> such that

tan(<em>θ</em>) = (56.5 N) / (106.5 N)   →   <em>θ</em> ≈ 28.0°

i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive <em>x</em>-axis.)

4 0
2 years ago
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