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3 years ago

The slope on a distance-time graph shows a ball moving from 20 m to 40 m in 1 s and from 40 m to 80 m in the next second

Physics

1 answer:

eduard3 years ago

8 0

The ball is accelerating

Explanation:

On a distance-time graph, the slope of the graph represents the speed of the object represented.

Let's therefore calculate the slope (so, the speed of the ball) in the two intervals given.

In the first second, we have:

$\Delta y = 40 - 20 = 20 m\\\Delta x = 1 s$

So the average speed is

$v_1 = \frac{\Delta y}{\Delta x}=\frac{20}{1}=20 m/s$

In the next second, we have:

$\Delta y = 80 - 40 = 40 m\\\Delta x = 1 s$

So the average speed is

$v_2 = \frac{\Delta y}{\Delta x}=\frac{40}{1}=40 m/s$

We notice that the speed of the ball has increased from 20 m/s in the first second to 40 m/s in the next second: this means that the speed of the ball is increasing, and therefore, the ball is accelerating.

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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A group of 25 particles have the following speeds:

svp [43]

Answer:

Part a: The average speed is 24.12 m/s

Part b: The rms speed is 25.55 m/s

Part c: The most probable speed is 17 m/s.

Explanation:

Part a

Average Speed

<em>Average speed is given as </em>

<em /> $v_{avg}=\frac{\sum}{n}$

$v_{avg}=\frac{(2 \times 11) +(7 \times 17)+(4 \times 19)+(3 \times 27) +(6 \times 32) +(1 \times 33)+(2 \times 40) }{25}\\v_{avg}=\frac{22+119+76+81+192+33+80}{25}\\v_{avg}=\frac{603}{25}\\v_{avg}=24.12 m/s$

So the average speed is 24.12 m/s

Part b

RMS Speed

$v_{rms}=\frac{\sum v^2}{n}$

$v_{rms}=\sqrt{\frac{(2 \times 11^2) +(7 \times 17^2)+(4 \times 19^2)+(3 \times 27^2) +(6 \times 32^2) +(1 \times 33^2)+(2 \times 40^2) }{25}} \\v_{rms}=\sqrt{\frac{242+2023+1444+2187+6144+1089+3200}{25}}\\\\v_{rms}=\sqrt{\frac{16329}{25}}\\v_{rms}=\sqrt{653.16}\\v_{rms}=25.55 m/s$

So the rms speed is 25.55 m/s

Part c

Most Probable Speed

As 7 particles have speed of 17 m/s i.e. 7 is the highest frequency so 17 m/s is the most probable speed.

3 0

3 years ago

What frequency must a sound wave have in air to have the same wavelength as a 750 Hz sound wave in a platinum bar? Vair = 340 m/

amm1812

Answer:

f = 91.1 Hz

Explanation:

As we know that it is given here that wavelength of sound in platinum is same as the wavelength of sound in air

so we can use the formula of wavelength in two mediums

$\frac{speed}{frequency} = \frac{speed}{frequency}$

now it is given that

$v_{air} = 340 m/s$

$v_{pt} = 2800 m/s$

frequency of sound in platinum is 750 Hz

now frequency of sound in air = f

now from above formula

$\frac{340}{f} = \frac{2800}{750}$

$f = 91.1 Hz$

7 0

3 years ago

A 100 kg father and his 50 kg daughter stand on ice skates on a frozen pond. The daughter pushes on her father with a force of 5

Lana71 [14]

Answer:

Both feel same magnitude force.

Explanation:

Given that

Mass of father = 100 kg

Mass of daughter = 50 kg

From the third law of Newtons :

Every action have it reaction in opposite direction.It means that if any object apply a force on the other object then first object also feel force of same magnitude but in opposite direction.

It means that both father and her daughter will feel same magnitude of same but in opposite direction.

7 0

3 years ago

Read 2 more answers

Can someone please answer my question please. thank you ❤️

faust18 [17]

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