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3 years ago

Why will a change in velocity have a greater affect on KE than a change in mass?

Physics

2 answers:

Sever21 [200]3 years ago

5 0

Answer: the answer is corect of what everone else said

Explanation:

lys-0071 [83]3 years ago

5 0

Answer:

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[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

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A bicycle has a momentum of 23.4

Snowcat [4.5K]

Momentum=23.4kgm/s
Velocity=2m/s

$\\ \rm\longmapsto Momentum=Mass\times velocity$

$\\ \rm\longmapsto Mass=\dfrac{Momentum}{Velocity}$

$\\ \rm\longmapsto Mass=\dfrac{23.4}{2}$

$\\ \rm\longmapsto Mass=11.7kg$

4 0

3 years ago

MamaMia's Pizza purchases its pizza delivery boxes from a printing supplier. MamaMia's delivers on-average 200 pizzas each month

Ira Lisetskai [31]

Answer:

a) 138 units

b) 17 units

c) 17 units

d) Total Cost = $353.35

Explanation:

Given:

Average pizzas delivered = 200

Charge of inventory holding = 30% of cost

Lead time = 7 days

Now,

a) Economic Order Quantity = $\sqrt\frac{2\times\textup{Annual Demand}\times\textup{Cost per Order}}{\textup{Carrying cost}}$

also,

Annual Demand = 200 × 12 = 2400

Cost per Order = Cost of Box + Processing Costs

= 30 cents + $10

= $10.30

and, Carrying Cost = $\frac{\textup{Total Inventory Cost}}{\textup{total annual demand}}$

= $\frac{\textup{Total Cost per order}\times\textup{Annual demand}\times\frac{25}{100}}{\textup{Annual demand}}$

= $\frac{\$10.30\times2400}\times\frac{25}{100}}{2400}$

= $2.575

Therefore,

Economic Order Quantity = $\sqrt\frac{2\times\textup{2400}\times\textup{10.30}}{\textup{2.575}}$

= 138.56 ≈ 138 units

b) Reorder Point

= (average daily unit sales × the lead time in days) + safety stock

= ( $\frac{200}{30}\times7$

= 46.67 ≈ 47 units

c) Number of orders per year = $\frac{\textup{Annual Demand}}{\textup{Economic order quantity}}$

= $\frac{\textup{2400}}{\textup{138}}$

= 17.39 ≈ 17 units

d) Total Annual Cost (Total Inventory Cost)

= Ordering Cost + Holding Cost

Now,

The ordering Cost = Cost per Order × Total Number of orders per year

= $10.30 × 17

= $175.1

and,

Holding Cost = Average Inventory Held × Carrying Cost per unit

Average Inventory Held = $\frac{\textup{0+138}}{\textup{2}}$ = 69

Carrying Cost per unit = $2.575

Holding Cost = 69 × $2.575 =

$177.675

Therefore,

Total Cost = Ordering Cost + carrying cost

= $175.1 + $177.675 = $353.35

5 0

3 years ago

Read 2 more answers

The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou

zlopas [31]

Answer:

q = 3.6 10⁵ C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

r = 6 , 37 106 m

E = k q / r²

q = E r² / k

q = $\frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}$

q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

r = 0.6 r_ Earth

r = 0.6 6.37 10⁶ = 3.822 10⁶ m

E = k q / r²

q = E r² / k

q = $\frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}$

q = 3.6 10⁵ C

4 0

3 years ago

A soccer player kicks a soccer ball with a force of 1.8 N. If the mass of the ball is .43 kg. How fast will the ball accelerate?

Vesnalui [34]

Answer:

The acceleration of the ball is 4.18 [m/s^2]

Explanation:

By Newton's second law we can find the acceleration of the ball

$F = m*a\\where:\\F = force applied [N] or [kg*m/s^2]\\m = mass of the ball [kg]\\a = acceleration [m/s^s]$

Now we have:

$a = F/m\\a = \frac{1.8 [kg*m/s^s]}{0.43[kg]} \\a = 4.18 [kg]$

4 0

3 years ago

Read 2 more answers

a star has a distance of 30 parsecs and a apparent magnitude of 3 --what would its absolute magnitude be?

Alborosie

The absolute magnitude of the star would be +5.

8 0

1 year ago