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3 years ago

Why will a change in velocity have a greater affect on KE than a change in mass?

Physics

2 answers:

Sever21 [200]3 years ago

5 0

Answer: the answer is corect of what everone else said

Explanation:

lys-0071 [83]3 years ago

5 0

Answer:

..: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website[02/06, 6:21 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:16 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website

[02/06, 7:22 PM] DHARUN ARULSELVAN: Check website[02/06, 7:25 PM] Nabhaan: Check website

[02/06, 7:25 PM] Nabhaan: Check website

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Fifty grams of water cooled from 50 'C to 10 'C. If the specific heat of water is 4.2 , how much heat was released ?

ryzh [129]

THe anwser woul have to be C

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3 years ago

How is calculating amplitude

kykrilka [37]

It is same as calculating maths for math

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3 years ago

How far can a bike rider traveling at 5.2 m/s go in 15 seconds

frez [133]

If he's traveling at 5.2 m/s, then he covers
5.2 meters in the 1st second
5.2 meters in the 2nd second
5.2 meters in the 3rd second
5.2 meters in the 4th second
.
.
.
.
5.2 meters in the 14th second, and
5.2 meters in the 15th second.

He covers 5.2 meters 15 times in 15 seconds.
To find the total distance, you could write down 5.2 meters
15 times and add them all up. Or you could use the newly-
discovered, labor-saving process called 'multiplication' to do
the same thing. With multiplication, it can be done in one line:

(5.2 m/s) x (15 sec) = 78 meters .

7 0

3 years ago

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 11.8 cm^2 is rotated during the time interval 4.9

Zanzabum

Answer:

Explanation:

Flux through the coil = nBA , n is no of turns , B is magnetic flux and A a is area of the coli

= 200 x 5.6 x 10⁻⁵ x 11.8 x 10⁻⁴

= 13216 x 10⁻⁹ weber .

b ) When the coil becomes parallel to magnetic field , flux through it will become zero.

c ) e m f induced = change in flux / time

= 13216 x 10⁻⁹ / 4.9 x 10⁻²

= 2697.14 x 10⁻⁷ V

= 269.7 x10⁻⁶

269.7 μV.

6 0

4 years ago

Consider a long, cylindrical charge distribution of radius R with a uniform charge density rho. Find the electric field at dista

Flauer [41]

Answer:

E = p*r / 2*e_o

Explanation:

Given:

- Volume of cylinder V = pi*r^2*L

- Surface area A = 2*pi*r*L

- permittivity of space : e_o

Find:

Electric field E at distance r from the axis, where r < R.

Solution:

Step 1: Application of Gauss Law

- Form a Gaussian surface within the cylinder with r < R. Th cylinder has two surfaces i.e curved surfaces and end caps. Due to long charge distribution the flux through is zero, since the surface dA of end cap and E are at 90 degree angle to one another; hence, E . dA = E*dA*cos(90) = 0. For the curved surface we have:

(surface integral) E.dA = Q_enclosed / e_o

Step 2: The charge enclosed (Q_enclosed) is function of r and proportional density:

Q_enclosed = p*V

Q_enclosed = p*pi*r^2*L

Step 3: The area of the curved surface:

dA = 2*pi*r*L

Step 4: Compute E:

E*(2*pi*r*L) = p*pi*r^2*L / e_o

E = p*r / 2*e_o

5 0

3 years ago