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max2010maxim [7]
2 years ago
11

Pair of angles are always concurrent to each other

Mathematics
1 answer:
Harrizon [31]2 years ago
3 0
PAIRS OF ANGLES ARE ALWAYS CONCURRENT TO EACH OTHER
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Evaluate the following expression using the values given: Find -3a2 - b3 + 3c2 - 2b3 if a = 2, b = -1, and c = 3. Numerical Answ
umka2103 [35]


sub values of a, b and c into the equation.

(-3x2x2)-(-1x3)+(3x3x2)-(2x3x2)-(2x-1x3)

(-12)-(-3)+(18)-(12)-(-6)

=3

4 0
3 years ago
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What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)
timurjin [86]
Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}

 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}
5 0
2 years ago
Зу = -2 - 6<br> 3y = 2z - 6
aleksandrvk [35]

Answer:

y = -8/3, z = -1

5 0
2 years ago
Round this to the nearest thousand. 4,589,215
defon
<span>Round this to the nearest thousand. 4,589,215
= </span>4,589,000
6 0
3 years ago
Read 2 more answers
Please help asap!!!!
d1i1m1o1n [39]

Answer:

i think you should do multiplication  

Step-by-step explanation:  I hope that helps.

4 0
2 years ago
Read 2 more answers
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