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max2010maxim [7]
3 years ago
11

Pair of angles are always concurrent to each other

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0
PAIRS OF ANGLES ARE ALWAYS CONCURRENT TO EACH OTHER
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The image of the point (2, 1) under a translation is (5, -3). Find
Yanka [14]

Answer:

The coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

Step-by-step explanation:

The image of the point (2, 1) under a translation is (5, -3).

It means when we horizontally move 3 units to the RIGHT i.e. adding 3 units to the x-coordinate and vertically move 4 units DOWN i.e. subtracting 4 units from the y-coordinate of the original point (2, 1), we get the coordinates of the image (5, -3).

Thus,

The rule of translation can be formulated such as:

(x, y) → (x + 3, y - 4)

(2, 1) → (2 + 3, 1 - 4) → (5, -3)

Thus,

Under the same rule of translation, we can determine the coordinates of the image of the point (6,6):

(x, y) → (x + 3, y - 4)

(6, 6) → (6 + 3, 6 - 4) → (9, 2)

Therefore, the coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

4 0
3 years ago
If I had 81.8*10^0,would my answer be 81.8
erastova [34]
Yes, it would still remain the same.
4 0
3 years ago
Read 2 more answers
A tree 7ft y’all grows an average 6 in each year which equation models the trees height h after x years
pentagon [3]

Answer:

h = 7 + 6x

Step-by-step explanation:

Since we are trying to find the height of the tree, we put h on the left side of the equation. Since the tree is 7ft tall at the moment, we write 7ft on the right side of the equation. Knowing that the tree grows 6 inches each year (x) we write 6x on the right side of the equation.

8 0
4 years ago
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Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
3 years ago
What is the solution to 0.6(24x-32)=0.8(24-6x)?​
Helen [10]
You would have to move terms which will bring you to 14.4 x - 19.2 = 19.2 - 4.8x the you would combine like terms then you would get 19.2x= 38.4 then you divide both sides by 19.2 and get 2 as your answer.
5 0
3 years ago
Read 2 more answers
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