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Evgesh-ka [11]
3 years ago
12

After reading a book for English class, 100 students were asked whether or not they enjoyed it. Nine twenty-fifths of the class

did not like the book. How many students liked the book?
Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0

Multiply 20/5 by nine so 20/5 simplify into 4 4 times nine is 36, so only 36 kids liked the book
skelet666 [1.2K]3 years ago
5 0

Answer: 64 students


Step-by-step explanation:

Given: Total students in English class= 100

Nine twenty-fifths of the class did not like the book.

⇒ \frac{9}{25} of class did not like the book.

Thus, the number of students did not like the book=\frac{9}{25}\times100=36

Therefore, the number of students like the book =Total students- students did not like the book

=100-36=64 students.

The number of students like the book =64

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Give an example of a benchmark fraction and an example of a mixed fraction.
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Answer:

Benchmark fractions: 4/12    5/12        6/12           7/12  

Mixed Fractions: 1 1/2      2 3/4               5 1/4          8 2/8

Step-by-step explanation:

A mixed fraction is simply a fraction with a whole number.

A benchmark fraction is a fraction used to compare and order other fractions.

8 0
3 years ago
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alex41 [277]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Which statement is true
Oxana [17]
The last statement is true
7 0
2 years ago
Is the following true or false? d/dx[x^3e^x]=x^2e^x (3x+2)
wolverine [178]
It's false. It's a product so...
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3 0
3 years ago
A bulb can either be on or off. A board contains connected to a randomization circuit that lights up a random sequence every tim
kari74 [83]

The question is incomplete. The complete question is :

A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence every time it is turned on. What is the probability that all the lights will switch on ?

Solution :

It is given that :

There is board connected to = 20 bulbs

And one can either be put ON or put OFF.

Therefore the chance that a bulb is ON = $\frac{1}{2}$

It is given that every time a bulb turns ON, the board lights up in a random sequence.

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3 years ago
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