If you sketch the path of the boat, you will form a right triangle towards the port. The distance from the port to the present position is the hypotenuse since it is opposite from the right angle formed by the 12 miles north and 5 miles east movement. Since it is a right triangle, use the Pythagorean Theorem to solve the hypotenuse.
Solution:
h² = o² + a²
h² = 12² + 5²
h² = 144 + 25
h² = 169
√h² = √169
h= 13
The present distance of the boat from the port is 13 miles.
Answer:
10+3pi
Step-by-step explanation:
The perimeter of of the shaded region is
AC+CT+marcSBT+SA
*Finding AC
The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.
*Finding CT
CT=RT-RC where RC is the width of the rectangle
Also RT is a radius so we have that
CT=6-RC
*Finding marcSBT
The circumference of a whole circle is 2pi*r.
We have a quarter of this with r=6.
1/4*2pi(6)
1/4*12pi
3pi
*Finding SA
SA=RS-AR
RS is a radius of the circle and AR is the length of the rectangle.
So we have that this can be rewritten as
SA=6-AR
Let's put these parts together:
6+6-RC+3pi+6-AR
Simplifying:
18-RC-AR+3pi
18-(RC+AR)+3pi
18-8+3pi (Remember length plus width equal 8)
10+3pi
In order to answer this, we will first need to combine like terms on each side. on the left, you can leave them alone. however on the right, we will need to combine 2 and 11. this is 13. the right side becomes 13-16y. after that, we can add 20y to both sides. that equals 15=13+4y now we can subtract 13 from both sides. 2=4y. then we divide by 4 on both sides to find y. y=.5
Is this question correct ?
Answer:
3.
Step-by-step explanation:
15 - 12 = 3.
The ends of the box are the lower and upper quartiles.
The difference upper - lower = the interquartile range.
