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AURORKA [14]
3 years ago
11

Which type of worker has a career that can be important in both maintenance/operations services and construction services? mecha

nical door repairers plumbers surveyors construction managers
Computers and Technology
2 answers:
ch4aika [34]3 years ago
6 0

Answer: mechanical door

Explanation:

Evgesh-ka [11]3 years ago
3 0

<u>Answer is:</u>

construction managers


<u>Explanation:</u>

why this answer because managers are manages the whole things and do check on every thing that can happened in services of maintenance and operations. So that is why this is the answer for this question.

I hope you get the idea. Thanks

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Please write a complete program to calculate monthly payment given
jasenka [17]

Explanation:

Code with comments:

#include <stdio.h>

#include <math.h>  

/* math library is required to use pow() function

First we need to create a function to calculate the Monthly Payment

It would take three inputs Rate, Years, and Principle amount

Then we converted the Rate and Months according to problem statement

pow() function is used to find (1+R)^M

Then finaly this function returns the value of Monthly Payment  */

float MonthlyPay(float R, int M, int P)

{

    R=R/1200;

    M=M*12;

   float po=pow((1+R),M);

   float PayM=(R+(R/(po-1)))*P;

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}

/*  In the main() function we get 3 inputs from the user Years, Rate and Principle amount

then we call the MonthlyPay function and pass it 3 inputs that we got from the user

then we calculated the total Payment by multiplying the Monthly Pay and total number of months

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int main(void)

{

    float Rate;

    int Year, Amount;

    printf("Enter Years: ");

    scanf("%d",&Year);

    printf("Enter Rate: ");

    scanf("%f",&Rate);

    printf("Enter Principle Amount: ");

    scanf("%d",&Amount);

   

    float Pay = MonthlyPay(Rate, Year, Amount);

    printf ("Monthly Payment is: %f \n", Pay);

    float totalPay=Pay*Year*12;

    printf ("Total Payment is: %f \n", totalPay);

    float interest=totalPay-Amount;

    printf ("Interest Expense is: %f \n", interest);

    return 0;

}

Output:

Enter Years: 5

Enter Rate: 7

Enter Principle Amount: 12200

Monthly Payment is: 241.572767

Total Payment is: 14494.367188

Interest Expense is: 2294.367188

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