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eimsori [14]
3 years ago
7

6x + 10x = 64 what does x equal?

Mathematics
2 answers:
Crazy boy [7]3 years ago
7 0

6x+10x=64

6x+10x

16x=64

\frac{16x}{16}=\frac{64}{16}

x=4

x=4 is correct answer.

Hope this helps!

Thanks!

-Charlie

Nutka1998 [239]3 years ago
6 0
X= 4
You add 6x and 10x then divide 16x from 64 which makes x=4
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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
A car drvies at a speed of 60 mph for 30 minutes. Calculate how far it travles
Studentka2010 [4]

Answer:

30 miles

Step-by-step explanation:

Distance = speed x time

30 minutes can be considered as ½ an hour.

60 x ½=30miles

8 0
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When will there be 0 pennies in the jar?how did you figured this out?
siniylev [52]
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On Monday the temperature was 3 degrees below 0 on Tuesday the temperature was 7 degrees what was the change in temperature
PIT_PIT [208]

Answer:

10 degrees

Step-by-step explanation:

7 - (-3) = 7+3 = 10 degrees

6 0
3 years ago
Find the equation of the parabola with focus (5, 1) and directrix y = -1.
Mumz [18]
Check the picture below.

since the focus point is above the directrix, that simply means the parabola is a vertical one, and therefore the square variable is the "x".

keeping in mind that, there's a distance "p" from the vertex to either the focus point or the directrix, that puts the vertex half-way between those fellows, in this case at 0, right between 1 and -1, as you see in the picture, and the parabola looks like so.

since the parabola is opening upwards, the value for "p" is positive, thus

\bf \textit{parabola vertex form with focus point distance}
\\\\
\begin{array}{llll}
4p(x- h)=(y- k)^2
\\\\
\boxed{4p(y- k)=(x- h)^2}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ( h, k)\\\\
 p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=5\\
k=0\\
p=1
\end{cases}\implies 4(1)(y-0)=(x-5)^2
\\\\\\
4y=(x-5)^2\implies  y=\cfrac{1}{4}(x-5)^2

8 0
3 years ago
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