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wel
2 years ago
11

Suppose you are determining the growth rate of two species of plants. Species A is 12 cm tall and grows 2 cm per month. Species

B is 10 cm tall and grows 3 cm per month. Which system of equations models the height of each species A(m) and B(m) as a function of months m.
Mathematics
1 answer:
SashulF [63]2 years ago
5 0
The answer is
A(m) = 12 + 2m
B(m) = 10 + 3m

m - the number of months
F(m) - growth in a function of months m

Species A is 12 cm tall, so the number 12 is independent on a number of months. But it <span>grows 2 cm per month. This means that in m months it will grow 2 * m. So, its function is: A(m) = 12 + 2m

Similarly, s</span>pecies B is 10 cm tall, so the number 10 is independent on a number of months. But it grows 3 cm per month. This means that in m months it will grow 3 * m. So, its function is: B(m) = 10 + 3m
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Answer:

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<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

4x² - 5 = 75

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Addition Property of Equality] Add 5 on both sides:                                    4x² = 80
  2. [Division Property of Equality] Divide 4 on both sides:                                  x² = 20
  3. [Equality Property] Square root both sides:                                                    x = ±2√5
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20
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{ x^2+3x-4}

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }

= \frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}

= \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= { (x-1)(x+4)}

= { x^2+3x-4}

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