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Zigmanuir [339]

3 years ago

5

A school library has 260 DVDs in its collection. Given that 45% of the DVDs are about science and 40% or about history how many

of the DVDs are about other subjects?

1 answer:

worty [1.4K]3 years ago

7 0

39 DVDs are about other subjects

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I have no idea how to slove this 5x-5 =2×+97

galina1969 [7]

Answer: x=34

Step-by-step explanation:

1. You subtract 2x from 5x on the other side to get rid of the 2x leaving you with 3x.

2. Then you add 5 to 97 to get rid of the -5, giving you 102 on the opposite side.

3. divide 102 by 3x giving you 34.

5x-5=2x+97

-2x -2x

3x-5=97 <u><em>X=102</em></u>

+5 +5

3x=102

x/3 102/3

4 0

3 years ago

Read 2 more answers

Can you go 24.3 miles with 15.3 gallons of gas

Andrew [12]

Answer:

yes you can go 24.3miles with 15.3 gallons of gas

Step-by-step explanation:

6 0

1 year ago

If BTS=GHD BS=25 TS=14 BT=31 GD=4x-11 S=56 B=21 and H=(7y+5) find the values of x and y

77julia77 [94]

Given:

Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.

To find:

The values of x and y.

Solution:

We have,

$\Delta BTS\cong \Delta GHD$ (Given)

$BS=GD$ (CPCTC)

$25=4x-11$

$25+11=4x$

$36=4x$

Divide both sides by 4.

$9=x$

In ∆BTS,

$\angle B+\angle T+\angle S=180^\circ$ (Angle sum property)

$21^\circ+\angle T+56^\circ=180^\circ$

$77^\circ+\angle T=180^\circ$

$\angle T=180^\circ-77^\circ$

$\angle T=103^\circ$

Now,

$\angle T=\angle H$ (CPCTC)

$103=7y+5$

$103-5=7y$

$98=7y$

Divide both sides by 7.

$14=y$

Therefore, the value of x is 9 and value of y is 14.

3 0

3 years ago

Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.

igomit [66]

Answer:

$y=\cot \theta$ and $y=\csc \theta$

Step-by-step explanation:

Note that if $\cos \theta=1,$ then $\sin \theta=0.$

Functions $y=\cos \theta,\ \ y=\sin \theta$ do not have vertical asymptotes at all.

Vertical asymptotes have functions $y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.$

Functions $y=\tan \theta$ and $y=\sec \theta$ have the same vertical asymptotes (when $\cos \theta =0$ ).

Functions $y=\cot \theta$ and $y=\csc \theta$ have the same vertical asymptotes (when $\sin \theta =0$ ). See attached diagram

3 0

3 years ago

16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.

Yuki888 [10]

Answer:

$W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}$

Observe that if the vector $x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ is in W then it satisfies:

$\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]$

This means that each vector in W can be expressed as a linear combination of the vectors $\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]$

Also we can see that those vectors are linear independent. Then the set

$\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\}$ is a basis for W and the dimension of W is 2.

7 0

3 years ago