Answer:
0.47
Step-by-step explanation:
f(x) = (x - 2)^(1/3)
average rate of change from x = -2 to x = 4 is [f(4) - f(-2)]/[4 - (-2)]
f(-2) = (-4)^(1/3) = -1.587401
f(4) = 2^(1/3) = 1.25992
[f(4) - f(-2)]/[4 - (-2)] = [1.25992 - (-1.587401)]/[4 - (-2)] = 0.47
Answer:
0.213 is the required probability.
Step-by-step explanation:
We are given the following information:
We treat person booking from online travel website as a success.
P(Booking through online travel website) = 0.68
Then the number of people follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 15
P(exactly ten people out of fifteen people used an online travel website)
0.213 is the probability that exactly ten people out of fifteen people used an online travel website when they booked their hotel.
Answer:
<h2>{5}</h2>
Step-by-step explanation:
The way you find profit is to subtract the revenue and the cost
Profit = Revenue - Cost
The revenue is the amount of money coming in, the cost is the amount of money going out. The goal of course is to have the revenue larger than the cost so that the profit is positive.
So the equation given is
P = 7.5n - (2.25n+15)
and its in the form
P = R - C
where...
R = 7.5n is the revenue equation
C = 2.25n+15 is the cost equation
Focus on the revenue equation
R = 7.5n
which is the same as
R = 7.50*n
This tells us that Sandra pulls in a total of 7.50*n dollars where n is some positive whole number. It represents the number of necklaces sold. For example, if she sold n = 10 necklaces, then
R = 7.50*n
R = 7.50*10
R = 750
meaning that Sandra has made $750 in revenue
As you can see above, the revenue is computed by multiplying the price per necklace ($7.50) by the number of necklaces sold (n) to get R = 7.50*n
So that's why the answer is $7.50
Note: The 2.25 is part of the cost equation. This is known as the variable cost. It is the cost to make one necklace ignoring the fixed cost (eg: rent). The variable cost often doesn't stay the same, but algebra textbooks often simplify this aspect.
