Answer:
168
Step-by-step explanation:
6% of 200 is 12. So 12 spots are reserved for handicap. If an additonal 20 spots are suitable for compact cars only then we have to subtract that as well since we want to find the spots that are A. not reserved for hanicap and B. suitable for non-compact cars. 12 + 20 - 32. Then, 200 - 32 equals 168.
Answer:
Are you sure it ia not x2 - x1 in the denominator?
The numerical factor<span> of a </span>multiplication expression like 3x<span> is calied a coefficient</span>
Answer:
5 trips
Step-by-step explanation:
Note that the weight and volume of the load must not exceed the given maximum.
Volume of load = 19.8m^3
Density of load = 650kg/m^3
Mass of load = 19.8 × 650 = 12,870 kg
Given limits.
Volume = 4m^3
Mass = 3700kg
Assuming the truck is to carry 4m^3 of the load.
The mass of 4m^3 of the load is = 4 × 650 = 2600kg
Mass = 2600kg < 3700kg
Therefore it satisfies both conditions.
The number of trip the truck would make is;
N = total volume of load/ volume per trip
N = 19.8/4
N = 4.95
N = 5 trips