Answer:
The draw in the attached figure
Step-by-step explanation:
we know that
An office building has the shape of a right rectangular prism with a width 20 meters. length 40, height 60
so
The shape of one floor of the building is equal to the shape of the rectangular base of the prism
therefore
One floor of the building is a rectangle with
Length 40 m
Width 20 m
see the attached figure
Answer:
The correct option is;
∠ADB ≅ ∠CDB, ≅
and
≅
. So ΔABD ≅ ΔCDB by SAS
Step-by-step explanation:
The given parameters are;
The polygon given = Quadrilateral
The diagonal of the quadrilateral = BD
The length of the side AD = (2×y + 5) units
The length of the side CD = (y + 10) units
The given measure of ∠ABD = (2 × y + 25)°
The given measure of ∠CBD = 35°
When y = 5, we have by substituting the value of y into the equations representing the dimensions of the quadrilateral ABCD;
The length of the side AD = 2 × y + 5 = 2×5 + 5 = 15 units
∴ The length of the side AD = 15 units
The length of the side CD = (y + 10) units = (5 + 10) units = 15 units
∴ The length of the side CD = 15 units
The measure of ∠ABD = (2 × y + 25)° = (2 × 5 + 25)° = 35°
The measure of ∠ABD = 35°
Therefore;
∠ADB ≅ ∠CDB by substitution
≅
by reflexive property
≅
by substitution
∴ ΔABD ≅ ΔCBD by Side-Angle-Side rule of congruency
Answer:
The area of the larger parallelogram is
Step-by-step explanation:
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its corresponding sides is the scale factor
Let
z------> the scale factor
step 2
Find the area of the larger parallelogram
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z------> the scale factor
x------> the area of the larger parallelogram
y-------> the area of the smaller parallelogram
so
we have
substitute the values