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dedylja [7]
3 years ago
10

A printer needs 12,000 good copies of a flyer for a particular job. Previous experience has shown that she can expect no more th

an a 5% spoilage rate on this type of job. How many should she print to ensure 12,000 clean copies?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

12600

Step-by-step explanation:

5% of 12000 is 600 so just add them

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40 percent of what number equals 19.2
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NEED HELP ASAP!!! WILL GIVE BRAINLIEST!!!
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  (6, 6)

Step-by-step explanation:

Each grid square is 2 units. 10 units up from point P is 5 grid squares up, or 3 grid squares above the x-axis. The x-coordinate remains the same (6), and the y-coordinate is the one labeling the 3rd line above the x-axis: 6.

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Determin the time taken when distance is 7150 km and speed is 780 km​
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3 years ago
A carpet company advertises that it will deliver your carpet within 15 days of purchase. A sample of 49 past customers is taken.
Novosadov [1.4K]

Answer:

a) H_0: \mu\leq15\\\\H_1: \mu>15

b) The z-value (1.5) is smaller than z=1.645 (critical value), so it is in the "acceptance region". It failed to reject the null hypothesis.

c) The p-value (0.07) is greater than the significance level (0.05), so it failed to reject the null hypothesis.

d) In this case, the error we may hae comitted is a Type II error (failed to reject a null hypothesis that is false).

Step-by-step explanation:

We have to perfomr a hypothesis test on the mean, with known standard deviation of the population.

a) The null hypothesis is that the deliver time is 15 days or less.

The null and alternative hypothesis are then:

H_0: \mu\leq15\\\\H_1: \mu>15

The significance level is defined as 0.05.

b) The critical value of z for a one-side test (rigth side) and a significance level of 0.05 is z=1.645.

If the z-value for this sample is higher than 1.645, it is in the "rejection region".

Calculating the z-value:

z=\frac{M-\mu}{\sigma/\sqrt{n}}=\frac{16.2-15}{5.6/\sqrt{49}}=\frac{1.2}{0.8}=1.5

The z-value (1.5) is smaller than z=1.645 (critical value), so it is in the "acceptance region". It failed to reject the null hypothesis.

c) The p-value for z=1.5 is:

P(z>1.5)=0.067

The p-value (0.07) is greater than the significance level (0.05), so it failed to reject the null hypothesis.

d) There are two types of error:

Type I errors: happen when we reject a null hypothesis that is true.

Type II errors: happen when we failed to reject a null hypothesis that is false.

In this case, the error we may hae comitted is a Type II error.

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