Answer:
48 mph
Step-by-step explanation:
First we need to find the distance from Elkhart to Chicago. Toledo to Elkhart is 136 miles and Toledo to Chicago 244 miles.
So the distance from Elkhart to Chicago can be calculated, since Chicago is farther from Toledo than Elkhart, as: distance(Toledo to Chicago) - distance(Toledo to Elkhart). These distances are given in the problem, so the distance from Elkhat to Chicago is: 244 miles - 136 miles = 108 miles.
This problem basically wants to know the slowest you can be yet still ariving on time. If you are the minimum speed, you will arrive in Chicago exactly at 10:30 A.M. So you have 2 hours and 15 minutes(10:30 A.M - 8.15A.M.) to drive 108 miles.
15 minutes is a fourth of a hour, so you have 2.25hours to go through 108 miles.
The minimum speed you must maintain is 108mph/2.25h = 48mph.
W + y + v + 88 = 180
22 + y + 43 + 88 = 180
y = 27
-6/7 < -6.7
i hope this helps
<u><em>Answer:</em></u>
- 84x - 70
<em><u>Step-by-step explanation:</u></em>
We want to combine like terms:
-10 - 90x + 6x - 60
We can see (-10) and (-60) are both regular constants so:
- 10 - 60 = - 70
Then (-90x) and (+ 6x):
6x - 90x = - 84x
- 84x - 70
Answer:
Velocity = displacement / time
Distance = 3t^2 +2t +6 to find distance you need to plug in time = 2 sec
Distance = 3(2)^2 +2(2) +6
Distance = 3(4) +4 + 6
Distance = 12 + 4 +6
Distance = 22 meters
In this problem the displacement is the distance.
so
Velocity = 22 meters / 2 second
Velocity = 11 meters/second
Does this help?
Step-by-step explanation:
