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viktelen [127]
4 years ago
13

Does anyone know how to find indicated values??? I am struggling!

Mathematics
1 answer:
kotykmax [81]4 years ago
5 0

To solve this problem, we must understand function notation and the operations that go along with it. For Example, in this problem, f(x)g(x) means that we must multiply f(x) by g(x). What this means is we should multiply the functions by one another, as modeled below:

f(x)g(x)

(3x^2 + 5x)(7x +3)

To simplify this expression, we must use the FOIL method for multiplying binomials, which means we multiply together the first, outer, inner, and last terms and then add them together. This is modeled below:

(3x^2)(7x) + (5x)(7x) + (3x^2)(3) + (5x)(3)

To simplify this expression, we must first perform the multiplication within each term:

21x^3 + 35x^2 + 9x^2 + 15x

Next, we can add together the two terms with the same exponents:

21x^3 + 44x^2 + 15x

Therefore, your answer is 21x^3 + 44x^2 + 15x.

Hope this helps!

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Is this set of numbers a Pythagorean triple? yes or no
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<u>Answer</u>:- No.

<u>Explanation</u> :-

<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>

<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.

<u>Here</u>,

hypotenuse = 12 (as it is the longest side)

and other two sides are 6 and 9.

----> 6^2 + 9^2 = 12^2

----> 36 + 81 = 144

----> 117 = 144

Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.

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Answer:

9.2

Step-by-step explanation:

The given triangle is a right angled triangle. To solve for any of the side length of such triangle, apply the trigonometry ratio formula which can easily be remembered as SOHCAHTOA.

SOH is Sin θ = opposite/hypothenuse,

CAH is Cos θ = Adjacent/hypotenuse

TOA is Tan θ = Opposite/adjacent

Thus, in the right triangle given, we have:

θ = 38°

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We're going to use, sin θ = opposite/hypotenuse

Sin(38) = x/15

Multiply both sides by 15 to solve for x

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9.24 = x

<em>x ≈ 9.2 (to nearest tenth)</em>

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