Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer:
The probability of event A occurs but event B does not occur = P(A)* Probability of event B does not occur = 0.375
Step-by-step explanation:
The probability of event A occurring = 50% = 0.5
The probability of event B occurring = 25% = 0.25
Events A and B are non simultaneous events.
The probability of event B does not occur = 1 - P(B)
= 1- 0.25
= 0.75
So the probability of event A occurs but event B does not occur = P(A)* Probability of event B does not occur
= 0.5*0.75
= 0.375
Thank you.
Answer:
6 Ms Price
Step-by-step explanation:
Answer:
x=9
Step-by-step explanation:
combine like terms
4+5=9
9+6x=7x
to get 6x with 7x subtract 6x from both sides as its positive
6x-6x=0
7x-6x=x
9=x
x=9
