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3 years ago

Two solutions of an equation are (6, 5) and (8, 5). What could the equation be

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

An equation for those could be: x*y= t*y-10= 30 so x,y,t could be 6,5,8

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At a Road Race you have 60 3/4 feet available for a water station your tables are 6 3/4 feet long. How many tables can you line

Rainbow [258]

You can line up 9 tables for the water station.

8 0

3 years ago

Read 2 more answers

For each triangle below find the side that marked with the letter.

Flura [38]

Answer:

All to 1 decimal place

3) a = 11.4

4) b = 11.2

5) c = 4.5

6) e = 6.4

7) f = 30.8

8) g = 67.9

Step-by-step explanation:

Step-by-step explanation:

3) cos(18) = a/12

12xcos(18) = a

a = 11.4

4) tan(25) = b/24

b = 24xtan(25)

b = 11.2

5) cos(51) = c/7.2

c = 7.2xcos(51)

c = 4.5

6) sin(28) = e/13.6

e = 13.6 x sin(28)

e = 6.4

7) cos(47) = 21/f

f = 21/cos(47)

f = 30.8

8) sin(33) = 37/g

g = 37/sin(37)

g = 67.9

All to 1 decimal place

6 0

3 years ago

Find the area of the shape shown below. I NEED HELP NOWWWWWW

Varvara68 [4.7K]

Answer:

<h2> 12.5 units ${}^{2}$ </h2>

Step-by-step explanation:

Given figure : Trapezoid

Base sides,

a = 2.5

b = 7.5

Height ( h ) = 2.5

Now, finding the area:

$\frac{1}{2} (a + b) \times h$

Plug the values

$= \frac{1}{2 } \times (2.5 + 7.5) \times 2.5$

Calculate the sum

$= \frac{1}{2} \times 10 \times 2.5$

Reduce the numbers with G.C.F 2

$= 5 \times 2.5$

Calculate the product

$12.5 \: \: {units}^{2}$

Hope this helps...

Best regards!

8 0

3 years ago

This is about the cone formula. If you don't know it, please don't answer. If you do, PLEASE ANSWER.

lions [1.4K]

9514 1404 393

Answer:

(b) 10.5 in

Step-by-step explanation:

The formula for the volume of a cone is ...

V = 1/3πr²h . . . . . . for radius r and height h

Then the height is ...

h = 3V/(πr²)

Your cone has a volume V = 199 in³ and radius r = 4.25 in, so the height is ...

h = 3(199 in³)/(π(4.25 in)²) ≈ 10.52 in

The height of the cone is about 10.5 inches.

6 0

3 years ago

Suppose you have a random variable that is uniformly distributed between 1 and 29. what is the expected value for this random va

Kryger [21]

Assuming the distribution is continuous, you have

$\mathbb E(X)=\displaystyle\int_1^{29}\frac x{29-1}\,\mathrm dx=\dfrac1{28}\int_1^{29}x\,\mathrm dx=15$

If instead the distribution is discrete, the value will depend on how the interval of number between 1 and 29 are chosen - are they integers? evenly spaced rationals? etc

3 0

3 years ago