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Leya [2.2K]
2 years ago
8

A. 66 ft.3 B.80 ft.3 C.128 ft.3 D.256 ft.3 Please answer thank you!:)

Mathematics
1 answer:
Lelechka [254]2 years ago
4 0

Step-by-step explanation:

Volume of the shown figure would give the idea of amount of plaster required to give the shapes.

Volume of the small box = 1×1×2= 2ft³

Volume of the big box = 4×4×4=64ft³

Total vol of the model = 64+2=66ft³

optionA

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Step-by-step explanation:

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2 years ago
Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog
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Answer:

SE=\sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.35 (1-0.35)}{100}}=0.048

If we replace the values obtained we got:

0.35 - 1.96\sqrt{\frac{0.35(1-0.35)}{100}}=0.257

0.42 + 1.96\sqrt{\frac{0.42(1-0.42)}{150}}=0.443

The 95% confidence interval would be given by (0.257;0.443)

Step-by-step explanation:

Notation and definitions

X=35 number of people that agree.

n=100 random sample taken

\hat p=\frac{35}{100}=0.35 estimated proportion of people that agree

p true population proportion of peopl that agree

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The standard error is given by:

SE=\sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.35 (1-0.35)}{100}}=0.048

If we replace the values obtained we got:

0.35 - 1.96\sqrt{\frac{0.35(1-0.35)}{100}}=0.257

0.42 + 1.96\sqrt{\frac{0.42(1-0.42)}{150}}=0.443

The 95% confidence interval would be given by (0.257;0.443)

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