Answer:E) There are no real solutions
Step-by-step explanation:
Looking at the equation, x^2 +20= 4
It is a quadratic equation since the highest power of x is 2
Equation x^2 +20= 4 can be re- written as
x^2 +20= 4 = x^2 +20- 4 =0
x^2 +16= 0
x^2 + 0x +16= 0 - - - - - - - - -1
Solving with the general formula for quadratic equations,
x = [-b +/- √(b^2 -4ac)]/2a
From equation 1,
a = 1 (coefficient if x^2)
b = 0 (coefficient if x
c = 16 (value of the constant)
Substituting into the formula,
x = [-0 +/- √(0^2 -4×1×16)]/2a
= [0+/-√-64]/2×1
= +/-√-64]/2
= +/-8i/2
x= +/-4i
This is a complex number so,
There are no real solutions
