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nika2105 [10]
3 years ago
11

What is a simpler form of the radical expression? sqrt 36g^6 A. 36|g^3| B. 36g^4 C. 6|g^3| D. 6g^4

Mathematics
2 answers:
krok68 [10]3 years ago
8 0
First we write down this expression:
\sqrt{36* g^{6} }
We notice that 36 is a square of 6 so we write:
\sqrt{ 6^{2}*g^6 }

Now, square root we imply on each of factors (g^6 and 6 ^2)
we get.
6*|g^3|
The reason for absolute value is because of variable g.

Answer is C.
melomori [17]3 years ago
3 0

Answer:

Lesson 1 Unit 2: Roots and Radical Expressions

1 = a (no real root)

2 = c (-0.05)

3 = c (6lg^3l)

4 = d (5x^7y^8)

5 = a (3x^2/5y)

5/5 100%

Step-by-step explanation:


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Answer:

x = -5

Step-by-step explanation:

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Hope this helps.

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Step-by-step explanation:

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3 years ago
consider a sequence of independent tosses of a biased coin at times k=0,1,2,…,n. On each toss, the probability of Heads is p, an
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Answer:

1. p*(1-p)

2. n*p*(1-p)

3. p*(1-p)

4. 0

5. p^2*(1-p)^2

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Step-by-step explanation:

1. Let Ik denote the reward (possibly 0) given at time k, for k∈{1,2,…,n}. Find E[Ik].

E[Ik]=  p*(1-p)

2. Using the answer to part 1, find E[R].

E[R]=  n*p*(1-p)

The variance calculation is more involved because the random variables I1,I2,…,In are not independent. We begin by computing the following values.

3. If k∈{1,2,…,n}, then

E[I2k]= p*(1-p)  

4. If k∈{1,2,…,n−1}, then

E[IkIk+1]=  0

5. If k≥1, ℓ≥2, and k+ℓ≤n, then

E[IkIk+ℓ]=  p^2*(1-p)^2

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3 years ago
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