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zalisa [80]
3 years ago
8

Q. A dice shows the numbers 1 through 12, with one number showing each time the die is rolled. What is the probability of rollin

g a 7?
​
Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0

Answer:

1/12

Step-by-step explanation:

The total number is 12 (assuming the dice would be rolled 12 times) 7 is a number in the range and it will appear once in the 12 rolls because each number shows each time. 1 (how many times 7 will show)/ 12(total number of rolls)

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Identify the parts of the expression 4.2m + (8 , 2) - 6.
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The answe wo

Step-by-step explanation:

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Use the provided information below to identify each of Mr. Nicholson’s earning opportunities as arithmetic or geometric. For eac
natita [175]

Answer:

4,200

Step-by-step explanation:

$60,000 divided by 3,500 is 4,200

7 0
2 years ago
What differential equation is?
Blababa [14]

Answer:

In mathematics, a differential equation is an equation that relates one or more functions and their derivatives. In applications, the functions generally represent physical quantities, the derivatives represent their rates of change, and the differential equation defines a relationship between the two.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
Sorry if it's hard to see but can any one work this out plz <br>Much appreciated​
aleksley [76]

Answer:

x = 5.25

Step-by-step explanation:

width = x

length = (x + 8)

length that overlaps with width = (x + 8) - x = 8

perimeter (clockwise)

= 90

= x + 8 + (x + 8) + x + (x + 8) + x + 8 + (x + 8) + x + (x + 8)

= 8x + 6(8)

= 8x + 48

8x + 48 = 90

8x = 42

x = 5.25

4 0
3 years ago
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