Answer:
y = 1/2x + 1
In order to evaluate a slope that is perpendicular to the given equation, you need to find the opposite reciprocal of the original slope. This means you take the original slope, flip the numerator and the denominator, and change the sign in front.
-2 ⇒ 1/2
Next, we need to substitute the information given into the point-slope formula.
The point-slope formula is:
y - y₁ = m(x - x₁)
y - 1 = 1/2(x - 0)
y - 1 = 1/2x
y = 1/2x + 1
Therefore, the line perpendicular to y = -2x + 2 is y = 1/2x + 1.
-1(7+4b) - distribute the -1 to the expression
(-1 * 7) + (-1 * 4b) — ( + and - = - )when it is multiplied
= -7 - 4b — there is no like term to added to subtracted so it will stay as like
x(x^2 - 2xy+y^2) distribute x to all
= x(x^2) - x(2xy) + x(y^2)
= x^3 - 2x^2y + xy^2 in multiplication exponent add to similar variable
No like term to connect
-5x(-3+x)
= -5x(-3) -5x(+x). (- and - is +)
= 15x -5x. similar variable x so connect the like connect like term by subtracting them
= 10x
To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.
I will show you calculation for (5,-2)
plug into y>x
-2>5
which is clearly false.
plug into y<x+1
-2<5+1
or -2<6
which is also false.
hence (5,-2) is not in the solution.
Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.
Hence answer will be "No Solution from given choices".
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:
0.1 seconds
Step-by-step explanation:
10/100=0.1
