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3 years ago

The length of a rectangle is one unit shorter than one-sixth of the width, x.

1 answer:

7 0

Lets say that y represents length and x width.
From the text we can write:
y=x/6 - 1

Perimeter we calculate:
P = 2*x + 2*y

now we use y equation from above and put it in perimeter equation:

P = 2*x + 2*(x/6 - 1)
P = 2*(7x/6 - 1)
P = 7x/3 - 2

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In a group of 60 students, 12 students take Algebra I, 18 students take Algebra II, and 8 students take both subjects. How many

vodomira [7]

Since 8 students take both, that leaves only 4 students who take Algebra I alone.
Likewise since 8 students take both, that leaves 10 who only take Algebra 2
So out of the 60, twenty two are taking either Alg I Alg Ii or both.

That leaves 38 people who are not taking either.
b. 38

You can set this up using a 2 circle venn diagram. Just be sure to put the 8 who take both in first.

4 0

3 years ago

Read 2 more answers

Pls help i need it its area

SOVA2 [1]

3,800
because the rectangle area is 40x70 plus the triangle area is 40x50 divided by 2

3 0

3 years ago

Read 2 more answers

3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

3 years ago

What is the degree of the polynomial 2x3 - 3x2 + 4x + 5

tia_tia [17]

With polynomials the degree is the highest power x or whatever the variable is raised to. In this case, the degree is 3 since the highest power x is raised to is x^3

4 0

3 years ago

1. A baseball player got a hit 19 times in his last 64 times at bat.

fiasKO [112]

A) $Probability =0.297$

B)In 200 times he can hit 59 times !

<u>Step-by-step explanation:</u>

Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :

a. What is the experimental probability that the player gets a hit in an at bat?

According to question ,

Favorable outcomes = 19

Total outcomes = 64

Probability = (Favorable outcomes)/(Total outcomes) i.e.

⇒ $Probability = \frac{19}{64}$

⇒ $Probability =0.297$

b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?

According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :

⇒ $Hit =0.297(200)$

⇒ Hit = 59.36

Therefore , In 200 times he can hit 59 times !

4 0

3 years ago