Question

1. A baseball player got a hit 19 times in his last 64 times at bat.

Answer 1

A) $Probability =0.297$

B)In 200 times he can hit 59 times !

Step-by-step explanation:

Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :

a. What is the experimental probability that the player gets a hit in an at bat?

According to question ,

Favorable outcomes = 19

Total outcomes = 64

Probability = (Favorable outcomes)/(Total outcomes) i.e.

⇒ $Probability = \frac{19}{64}$

⇒ $Probability =0.297$

b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?​

According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :

⇒ $Hit =0.297(200)$

⇒ Hit = 59.36

Therefore , In 200 times he can hit 59 times !