Question

There are three exams in your linear algebra class, and you theorize that your score in each exam (out of 100) will be numerically equal to the number of hours you study for that exam. The three exams count 20%, 30%, and 50%, respectively, toward the final grade. If your (modest) goal is to score 76% in the course, how many hours a, b, and c should you study for each of the three exams to minimize quantity a2 b2 c2

Answer 1

Answer:

a) 40 hours

b) 60 hours

C) 100 hours

Step-by-step explanation:

0.2a + 0.3b+0.5c = 76

Hence: 0.2* (0.2 λ) +0.3*(0.3 λ )+0.5*(0.5 λ ) = 76

0.38 λ =76

λ = 76/0.38 =200

Thus : 40, 60, 100