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Ksenya-84 [330]
3 years ago
10

There are three exams in your linear algebra class, and you theorize that your score in each exam (out of 100) will be numerical

ly equal to the number of hours you study for that exam. The three exams count 20%, 30%, and 50%, respectively, toward the final grade. If your (modest) goal is to score 76% in the course, how many hours a, b, and c should you study for each of the three exams to minimize quantity a2 b2 c2
Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

a) 40 hours

b) 60 hours

C) 100 hours

Step-by-step explanation:

0.2a + 0.3b+0.5c = 76

Hence: 0.2* (0.2 λ) +0.3*(0.3 λ )+0.5*(0.5 λ ) = 76

0.38 λ =76

λ = 76/0.38 =200

Thus : 40, 60, 100

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Answer:

<u>5.56 hours</u>

Step-by-step explanation:

Margo read 42 pages in 2.5 hours.

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So, The number of pages that Pete reads = 42 - 6 = 36 pages

So, Pete read 36 pages in 2.5 hours.

let the time needed to read 80 pages x

∴ 36 pages ⇒ 2.5 hours

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∴\frac{36}{80} = \frac{2.5}{x}

Using cross multiplication:

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So, The time taken to read 80 pages

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What is the graph of the equation 4x – 5y = 15?
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Answer:

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Step-by-step explanation:

The given relation is as follows :

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When square gets removed from W, it goes to F and it will form as follows :

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