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yawa3891 [41]
2 years ago
10

Suppose y varies inversely with x, and y = a when x = a 2. What inverse variation equation relates x and y ?

Mathematics
1 answer:
Sphinxa [80]2 years ago
6 0

The variation equation is xy = a^3

<h3>How to determine the equation?</h3>

An inverse variation is represented as:

xy = k

Where k is the constant of variation

When y = a and x =a^2, we have:

k = a * a^2

Evaluate

k = a^3

Substitute k = a^3 in xy = k

xy = a^3

Hence, the equation is xy = a^3

Read more about variation at:

brainly.com/question/6499629

#SPJ1

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What is the sequence technique of this number sequence 3 20 78 334 1696 ?
polet [3.4K]
3×2+14=20
20×3+18=78
78×4+22=334
334×5+26=1696
1696×6+30=10206
Hence, the question mark should be replaced by 10206
3 0
4 years ago
1) what is the initial value?
JulsSmile [24]

Step-by-step explanation:

1) for t = 0, the initial value is -0.45 gal. which is funny. when it is really cold, do people add water to the tank somehow instead of consuming water ?

so I guess, that system is really reliable with values greater than 0.

0.0875t = 0.45

t = 5.142857143...°

so, I guess, 6° is the lowest reasonable value for this function.

2) as for any line function, the slope is the rate of change.

so, 0.0875 gal more per 1 degree more in temperature.

3) t = 90

w = 0.0875×90 - 0.45 = 7.425 gal

8 0
2 years ago
Three randomly selected households are surveyed. the numbers of people in the households are 1,3,8 assume that samples of size n
Naily [24]
I assumed that 3 households are sampled.
Now, is the number in each of these households equal to 1, 3 and 8 people?

Next, the question says, samples of n=2 are randomly selected (with replacement) from these 3.

So are sample space is
11
13
31
33
18
81
38
88
83
88

This is done 9 times.
Is that how you understand the problem?
When they select the household with only 1 person, the variance is 0
When they select the household with 8 people, they variance will be from a discrete uniform distribution

Similarly for household with 3 individuals.



5 0
3 years ago
The number of passengers who arrive at the platform of a subway station for the 10 am train is a random variable with a mean of
ludmilkaskok [199]

Answer:

The lower bound of the probability that there will be between 100 and 140 passengers 96%.

Step-by-step explanation:

The Chebyshev's theorem states that, the probability that <em>X</em> is within <em>k</em> standard deviation of mean is given by,

                                 P(|X-\mu|

Here, k is any positive number.

The given information is:

Mean (<em>µ</em>) = 120

Standard deviation (<em>σ</em>) = 16.

Then, we need to compute, P (100 ≤ X ≤ 140).

Then,  

\frac{Upper-\mu}{\sigma}=\frac{140-120}{\sqrt{16}}=5    

\frac{\mu-Lower}{\sigma}=\frac{120-100}{\sqrt{16}}=5              

Since, these two values coincide it implies that the event (66000, 78000) is centered about the mean.

Also, the event P (100 ≤ X ≤ 140) is equivalent to having X within 5 standard deviation of the mean.  

That is, <em>k</em> = 5.

Then for k = 5,  

1-\frac{1}{k^{2}}=1-\frac{1}{25}=\frac{24}{25}=0.96

That is, <em>P</em> (100 ≤ <em>X</em> ≤ 140) ≤ 0.96 .

Thus, the lower bound of the probability that there will be between 100 and 140 passengers 96%.

7 0
3 years ago
Find the midpoint between A and C.
Sloan [31]

Answer:

<h2>(0.5, 0.5)</h2>

Step-by-step explanation:

The formula of a midpoint of a segment AB with endpoints at A(x₁, y₁) and B(x₂, y₂):

M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

From the graph we have the points A(-2, 4) and C(3, -3).

Substitute:

M_{AC}(x,\ y)\\\\x=\dfrac{-2+3}{2}=\dfrac{1}{2}=0.5\\\\y=\dfrac{4+(-3)}{2}=\dfrac{1}{2}=0.5

6 0
3 years ago
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