3/5 + 3/20
=12/20 + 3/20
=15/20
1 - 15/20
=20/20 - 15/20
=5/20
=1/4
Answer:
It is not a subspace.
Step-by-step explanation:
So, the polynomial degree of at most 3 is given below as;
V = { p (z) = b0 + b1z + b2z^ + ... + bnz^n. |n is less than or equal to 3 and b0, b1, b2,... are integers.
To determine whether a subset is a subspace of Pn, we have to check for the properties below;
(1). Zero vector property : that is, when polynomial, p(z) = 0 and 0 is an integer.
(2). Addition property= here, we have; p(z) + h(z) = (b0 + b1z + b2z^2 +....+ bnz^n) + ( c0 + c1z + c^2z^2 +... + cnz^n). That is the sum of integers.
(3). Scaler multiplication property: the coefficient here may not be real numbers therefore, the condition is not followed here.
Therefore, it is not a subspace of Pn.
Step-by-step explanation:
x is the independent variable
y is the dependent variable
<span>y=1/5x+5 with the point (-6, 0)
The line perpendicular to this line will have a slope that's the negative reciprocal of this one. So if the slope here is 1/5 (based on y=mx+b, where m is the slope), then the perpendicular slope would be -5/1.
So now that you have the point and the slope, use the point-slope formula.
y - y</span>₁ = m(x - x₁)
m = -5
(x₁, y₁) = (-6, 0)
y - 0 = -5(x + 6)
y = -5x - 30
y = -5x - 30 is the line perpendicular to y=1/5x+5.