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lyudmila [28]
3 years ago
10

The radius of a circle measures 15 ft. What is the circumference of the circle?

Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

\boxed {\tt 94.2 \ feet}

Step-by-step explanation:

The circumference of a circle can be found using the following formula:

c= \pi d

where d is the diameter. We are given the radius, so let's find the diameter.

The diameter is twice the radius.

d=2r

The radius is 15 feet.

d= 2 * 15 \ ft

Multiply.

d= 30 \ ft

Now we know the diameter. Substitute 30 feet in for d.

c= \pi d

c=\pi * 30 \ ft

We are using 3.14 for pi, so substitute it in.

c=3.14 * 30 \ ft

Multiply.

c= 94.2 \ ft

The circumference of the circle is 94.2 feet.

kumpel [21]3 years ago
8 0
<h2>Answer:-</h2>

  • The required answer is 94.2 feet.

<h2>Solution:-</h2>

We have formula for this type Questions

c = πdc = πd

<h2>Here:-</h2>

  • d is the diameter.

We have radius in the Question so we can easily find diameter.

<h2>According to Question:-</h2>

The diameter is twice the radius.

=> d = 2rd = 2r

Also we know that the radius is 15 feet.

<h2>So:-</h2>

=> d = 2 * 15 \ ftd

=> d = 2∗15 ft

<h2>On Calculation:-</h2>

=> d = 30 \ ftd = 30 ft

=> c= \pi dc=πd

=> c=\pi * 30 \ ftc=π∗30 ft

=> c=3.14 * 30 \ ftc=3.14∗30 ft

=> c= 94.2 \ ftc=94.2 ft

<h2>Therefore:-</h2>

<h3><u>The required answer is 94.2 feet.</u></h3>
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(x,y)

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Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:
tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

  • 91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

  • 79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

Q1 = \frac{N +1}{4}th

So, we have:

Q1 = \frac{13 +1}{4}th

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<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

Q3 =  3 \times \frac{N +1}{4}th

So, we have:

Q3 =  3 \times \frac{13 +1}{4}th

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Q3 =  10.5th

This is the average of the 10th and the 11th element.

Q_3 =\frac12 \times (98 + 101)

Q_3 =99.5

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

IQR = Q_3 -Q_1

IQR = 99.5 - 87.5

IQR = 12

Also, we have:

IQR(1.5) = 12 \times 1.5

IQR(1.5) = 18

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

Lower = Q_1 - IQR(1.5)

Lower = 87.5- 18

Lower = 69.5

Upper = Q_3 + IQR(1.5)

Upper = 99.5 + 18

Upper = 117.5

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

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