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3 years ago

10

The base of a triangular prism is an isosceles right triangle with a hypotenuse of

2 answers:

Setler [38]3 years ago

6 0

SA= Lateral Area + Area (of base)

Lateral area = perimeter of base x height

An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.

So 5 + 5 + square root of 50 is your perimeter

Multiply the perimeter times your height (8) and you get the lateral area.

Add your lateral area to the base area (triangle = 1/2 bh)

LA = 136.568...
Area of Triangle base = 12.5

Surface area = 149.068... square cm

nalin [4]3 years ago

5 0

Are sure that is right

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irakobra [83]

Step-by-step explanation:

Given that,

Height of cylinder = 4 cm
Volume of cylinder = 616 cm³

To find,

Diameter of the base = ?

Firstly we'll find the base radius of the cylinder.

$\longmapsto\rm{V_{(Cylinder)} = \pi r^2h}\\$

<u>Accordi</u><u>ng</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>qu</u><u>estion</u><u>,</u>

$\longmapsto\rm{616= \dfrac{22}{7} \times r^2 \times 4}\\$

$\longmapsto\rm{616 \times 7 = 22 \times r^2 \times 4}\\$

$\longmapsto\rm{4312 = 88 \times r^2 }\\$

$\longmapsto\rm{\cancel{\dfrac{4312}{88}} = r^2 }\\$

$\longmapsto\rm{49 = r^2 }\\$

$\longmapsto\rm{\sqrt{49} = r }\\$

$\longmapsto\rm{7 \; cm = r }\\$

Now,

$\longmapsto\rm{Diameter = 2r }\\$

$\longmapsto\rm{Diameter = 2(7 \; cm) }\\$

$\longmapsto\bf{Diameter = 14 \; cm}\\$

The required answer is 14 cm.

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bogdanovich [222]

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Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?

nydimaria [60]

Answer:

Any equation of the line that is different from y=x is the solution to the problem.

Step-by-step explanation:

step 1

Find the slope of the line that passes through the points (1, 1) and (5, 5)

m=(5-1)/(5-1)=1

step 2

Find the equation of the line into slope point form

y-y1=m(x-x1)

we have m=1

(x1,y1)=(1,1)

substitute

y-1=(1)(x-1)

y=x-1+1

y=x

therefore

Any equation of the line that is different from y=x is the solution to the problem.

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3 years ago

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Lady bird [3.3K]

44.

1. Given

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4 years ago

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Inga [223]

Answer:

Step-by-step explanation:

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