Answer:
I hope you got it. I have presented it clearly and stepwise.
Write an equation of the line that passes through the point (-2,-4) with slope -6
2 answers:
The generic equation of the line is given by:
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line.
We have then that the slope of the line is:
The line passes through the point (-2, -4), therefore, the ordered pair is:
Substituting values we have:
Rewriting we have:
Answer:
An equation of the line that passes through the point (-2, -4) with slope -6 is:
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line.
We have then that the slope of the line is:
The line passes through the point (-2, -4), therefore, the ordered pair is:
Substituting values we have:
Rewriting we have:
Answer:
An equation of the line that passes through the point (-2, -4) with slope -6 is:
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Given:-
To find:-
The simplified form.
At first we take conjucate and multiply below and above.
The conjucate is,
So now we multiply. we get,
Now we simplify. so we get,
We know the value of,
Substituting the value -1. we get,
So now we split the term to bring it into the form a+ib. so we get,
So the required solution is,
Answer:
Let, the c.p be x.
Given,
profit % = 20%
S.P = rs 816
c.p = x
We know,
profit = p% of c.p
= * x
=
now,
C.p = profit + s.p.
x = + 816
x =
5x = x + 4080
5x-x = 4080
4x = 4080
x =
x = Rs 1080
Hence, the c.p is Rs. 1080