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Pavel [41]
3 years ago
6

3 divided into 99 equals what

Mathematics
2 answers:
Ede4ka [16]3 years ago
7 0
The answer is 33 because 3 * 30 = 90 and 3 * 3 = 9 If you add them together you would get 99. This means that 3 goes in 99, 33 times.
ELEN [110]3 years ago
3 0
3/99 = 1/33
So 3 ÷ 99 = 1/33 = 0.030303030303, or 33%
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The newspaper reported that the Dow Jones Industrials have had a low of 8,062 and a high of 11,350. The Dow Jones Transportation
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The stock market crash of 2020 began on March 9, 2020. The Dow fell a record 2,013.76 points to 23,851.02. It was followed by two more record-setting point drops on March 12 and March 16. The stock market crash included the three worst point drops in U.S. history.

Step-by-step explanation:

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In six grade class, 3/7 of the students are boys, and 5/8 of these boys are in Ms. Jones’ class. What fraction of the entire six
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Think of the entire population of 6th graders here. 3/7 are boys and 4/7 are girls. 5/8 of these boys are in Ms. Jones' class; that fraction would be (5/8)(3/7), or 15/56. This 15/56 represents the fraction of the entire sixth grade class who are in Ms. Jones' class.


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3 years ago
Read 2 more answers
How do you graph x = 1/4
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Step-by-step explanation:

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3 years ago
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Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
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