Two numbers that gives twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90 are -10 and 4
Given :
Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90.
Let a and b be the two unknown numbers
Lets frame equation using the given statements
Twice the sum of a number and 3 times a second number is 4.

the difference of ten times the second number and five times the first is 90

Now use these two equations to solve a and b

Add both the equations

Now find out 'a'

The two numbers are -10 and 4
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Answer:
three and seventy-five hundredths or three point seven five
Step-by-step explanation:
Answer:
Find the question mark using the model I've provided and that'll be the answer!
Answer:
The answer is A
Step-by-step explanation:
Answer:
It's the first option! :)
Step-by-step explanation:
2x + 2k = m, right?
So, to bring 2k alone, we'll subtract 2x.
2k = m - 2x
Now, we'll divide both sides by 2! ^ _ ^
k = (m - 2x) / 2
That's pretty much just the (1)st option! :)