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Katarina [22]
2 years ago
15

if a person earns $2600 in 4 weeks, how much can the person earn in 20 weeks at the same rate of pay?

Mathematics
1 answer:
AlladinOne [14]2 years ago
4 0

Howdy!

To do this we first have to find the unit rate of 2,600.

2,600/4=650 each week. Then, we just multiply 650x20, with 20 being the number of weeks.

650x20=13,000<---Answer

-Seth

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A scale drawing has a scale of 0.25 in. : 12 ft. Find the length on the drawing for an actual length of 15 ft.
lesya [120]

If 0.25 in on a drawing is 12 ft in real life, than 1 in on the drawing is 48 ft in real life.

Just divide 15 by 48

15/48=0.3125

So the length of 15 in real life to a drawing is 0.3125 inches.

7 0
2 years ago
The slope between (3, 9) &amp; (6, 12) m=
vivado [14]

Answer: m=1

Step-by-step explanation:

m = (y2 - y1)/(x2 - x1)

Where

y2=12

y1=9

x2=6

x1=3

so plug in your values in the slop formula:

m=(12-9)/(6-3)

=3/3

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6 0
2 years ago
A score of "3" on a par 5 hole is also known as a(n) _____.
den301095 [7]
The correct answer is "eagle." A score of "3" on a par 5 hole is also known as an eagle. Albatross on the other hand is <span>a score of 3-under par on a hole. </span><span> A birdie is universally known as a score of 1-under par on a hole. An </span>eagle<span> is 2-under par or 3-under par 5.</span>

Here are the choices.
eagle
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7 0
3 years ago
What equals 168 in multiplication
kifflom [539]
84 times 2 equals 168 in multiplication
5 0
3 years ago
Find the multiplicative inverse of 6 + 2i
Marina CMI [18]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2774989

________________


Find the multiplicative inverse of

\mathsf{z=6+2i}

________


The inverse multiplicative of  \mathsf{z=a+bi}  is

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\&#10;=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}

=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\&#10;\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}

________


For this question,

\mathsf{z=6+2i}


So,

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{6+2i}}\\\\\\&#10;=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\&#10;=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\&#10;=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}


\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

6 0
3 years ago
Read 2 more answers
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