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adoni [48]
3 years ago
13

Find the equation of the line that is parallel to the line x+3y=-15 that passes through the origin

Mathematics
1 answer:
Monica [59]3 years ago
5 0
You would subtract x from each side. It would then be 3y=-x-15. Then you would divide all of the equation by 3. Your final answer would be y=-3x-5.
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A train is traveling at a constant speed. The diagram represents the train's distance and time. What is the speed of the train?
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240÷6=40 so the answer would be "The train is traveling 40 miles per hour."
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The Jelly Junior High school color is made by mixing red paint with yellow paint. The ratio of red to yellow is 3 to 5. How much
user100 [1]
V/a = 3/5
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v = ...

3/5 = v/20
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What are like terms? How do you combine them? Can you give an example?
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Guys help plz and I will give brainliest
rewona [7]

Answer:

add 12 for all sides I think

Step-by-step explanation:

but if 12 yd is on both sides you must add 12+12 and the after getting the answer add then with 12+12

4 0
3 years ago
HELP ME!!!
larisa [96]

Answer:

  -2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

  A = (1/2)(f(a) +f(4))(4 -a)

  = (1/2)((3a -1) +(3·4 -1))(4 -a)

  = (1/2)(3a +10)(4 -a)

We want this area to be 12, so we can substitute that value for A and solve for "a".

  12 = (1/2)(3a +10)(4 -a)

 24 = (3a +10)(4 -a) = -3a² +2a +40

  3a² -2a -16 = 0 . . . . . . subtract the right side

  (3a -8)(a +2) = 0 . . . . . factor

Values of "a" that make these factors zero are ...

  a = 8/3, a = -2

The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

_____

<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.

5 0
3 years ago
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