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madreJ [45]
3 years ago
15

PLEASE HELP I need help on these questions

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Everything you're posting involves right triangles, and
each one is solved with the Pythagorean formula:

              (one leg)² + (other leg)² = (hypotenuse)²

For the tree . . .
Do you see the right triangle ?
They even marked a little box at the base of the stump
to remind you that there's a right angle there.

-- The stump is 3 meters high.
-- The broken part of the tree is on the ground
    13 meters away from the stump.
--  The broken part of the tree is the hypotenuse.
       (3)² + (13)² = (broken part)²

-- Before it fell over, the broken part stood on top of the 3-meter stump.

==========================================

#4).  Your coordinates for point 'G' are correct, but
the coordinates of point 'F' should be (-1, 6), not (1,6).
If you know how to calculate the distance between 2 points,
then that little correction might fix the problem you're having.

The distance between two points is

        Square root of [ (x₁-x₂)² + (y₁-y₂)² ]
or
       Square root of [ (difference of the x's)² + (difference of the y's)² ] .

Without even using this formula, you could just look at
the graph, and do something like this:

-- From 'F', draw a line 2 units straight down.

-- From 'G', draw a line 4 units to the left.

-- Connect 'F' and 'G' .

Now you have a little right triangle.
The legs are 2 units and 4 units.
The hypotenuse is the distance between 'F' and 'G'.

   (2)² + (4)² = (that distance)²
       
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5 0
3 years ago
Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare
leva [86]

Answer: x+3y=12

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is y=3x, then its slope = 3   [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}

Equation of line with slope n and passers through (a,b) is

(y-b)=n(x-a)

Equation of line with slope n= \dfrac{-1}{3} and passes through point ( 0,-4) :

(y-(-4))=\dfrac{-1}{3}(x-0)\\\\\Rightarrow\ y+4=\dfrac{-1}{3}x\\\\\Rightarrow\ -3(y+4)=x\\\\\Rightarrow-3y-12=x\\\\\Rightarrow x+3y=12

Hence, Required equation : x+3y=12

8 0
3 years ago
Please help...................
anastassius [24]

Answer:

I would help you

Step-by-step explanation:

But I'm really lazy and I really don't like math. I'm not good at it and I think I failed it last semester. true story bro.

7 0
3 years ago
Read 2 more answers
Find an angle between 0 and 360 degrees that is coterminal with 1260 degrees
cluponka [151]
1260-360-360-360=180
Therefore,180
4 0
3 years ago
Read 2 more answers
Select all expressions whose value is negative
il63 [147K]

Answer:

"2 + 2(-3)(7) = negative

-2(27 ÷ 9)+4= negative

(14 ÷ -2)(-6)= positive

(4 - 10) - ( 8 ÷ ( -2))= negative

Step-by-step explanation:

2 + 2(-3)(7) = -40

-2(27 ÷ 9)+4= -2

(14 ÷ -2)(-6)= 42

(4 - 10) - ( 8 ÷ ( -2))= -2"

5 0
3 years ago
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