A student raises her average grade from a 75 to a 90. What is the percent of the increase in the students average grade

1 answer:

5 0

Since grades are out of 100, you can just subtract 75 from 90 which is 15. the percent of increase in the student's grade is 15%

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What is the answer to this

olasank [31]

Three times the variable m minus four is equal to fourteen.

Another way could be:

Four less than three multiplied by m is equivalent to fourteen.

The first way I put it is simpler but if you really want to impress your teacher then I suggest going with the second way.

Also if you are looking to solve the equation then it would be:

3m - 4 = 14

+4 +4

------------

3m = 18

----- -----

3 3

m = 5

Hope that helped :-)

8 0

3 years ago

the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?

FinnZ [79.3K]

ANSWER

The other zero is

$x = - 10$

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.

We were given that the axis of symmetry of the quadratic equation is
$x = - 3$

We were also given that, one of the zeroes of the quadratic equation is
$x = 4$

Let the other zero of the quadratic equation be
$x = p$

,then, we apply the midpoint formula to find the value of
$p$

Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,

$\frac{x_1 + x_2}{2} = axis \: of \: symmetry$

We substitute to obtain,

$\frac{p + 4}{2} = - 3$

We multiply through by 2 to get,

$p + 4 = - 6$

This implies that,

$p = - 6 - 4$

$p = - 10$

3 0

3 years ago

Read 2 more answers

The table shows the battery lives in hours of ten Brand A batteries and ten Brand B batteries.

defon

Plotting the data (attached photo) roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.

In such a scenario, interquartile range is normally the best measure to compare variations of data.

Therefore, the last option is the best for the data provided.