Vertices A and B of triangle ABC are on one bank of a river, and vertex C is on the opposite bank. The distance between A and B
is 200 feet. Angle A has a measure of 33°, and angle B has a measure of 63°. Find b.
2 answers:
A suitable solver will tell you instantly that the measure of b is 179.18 ft.
_____
If you want to do it yourself (meaning also with the aid of a calculator), you can use the Law of Sines. The given side is side "c", so you need the measure of angle C. That will be
180° -33° -63° = 84°
Then side "b" can be found from
b/sin(B) = c/sin(C)
b = c*sin(B)/sin(C)
b = (200 ft)*sin(63°)/sin(84°) ≈ 179.183 ft
_____
If you want to do it yourself (meaning also with the aid of a calculator), you can use the Law of Sines. The given side is side "c", so you need the measure of angle C. That will be
180° -33° -63° = 84°
Then side "b" can be found from
b/sin(B) = c/sin(C)
b = c*sin(B)/sin(C)
b = (200 ft)*sin(63°)/sin(84°) ≈ 179.183 ft
You might be interested in
Answer:
x = 2
Step-by-step explanation:
Using Pythagoras identity in the right triangle
x² = 10² + 6² = 100 + 36 = 136 ( take the square root of both sides )
x = =
= 2