Ask question

Ask question

All categories

3 years ago

5

the elements carbon hydrogen and oxygen are all part of the same blank on the periodic table........ i i think GROUP diangol row

period

1 answer:

Mrrafil [7]3 years ago

6 0

The elements Carbon, Hydrogen, and Oxygen are all part of Non-Metals.

Hope This Helps! :)

You might be interested in

What is a mixture called when it has its different components mixed evenly within the substance? Heterogeneous mixture Homogeneo

larisa86 [58]

It would be considered a Homogeneous Mixture. A mixture with two or more components mixed evenly is a Homogeneous mixture.

3 0

4 years ago

Read 2 more answers

A. Clearly draw the Lewis structure for the PBr4- ion. Show your math where

Nataliya [291]

Answer:

Br

|

Br-P-Br

|

Br

Explanation:

To calculate the valance electrons, look at the periodic table to find the valance electrons for each atom and add them together. P is in column 5A, so it has 5, Br is in column 7A, so it has 7 (multiply by 4 since there are 4 Br atoms to give 28) and there is a 1- charge, so add one more electron. 5+28+1=34, so there are 34 electrons to place. P would be the central atom, so place it in the middle. Place each Br around the P (as shown above) with a a single line connecting it. Each line represents 2 electrons, so 8 total have been place, leaving 26 remaining. Place 6 electrons around each Br (2 on each of the unbonded sides), which leaves 2 electrons remaining. The remaining pair of unbound electrons will be attached to the P between any two Br atoms. Phosphorus doesn't have to follow the octet rule, so it actually ends up with 10 valance electrons.

4 0

3 years ago

Read 2 more answers

Fill in the blank with the correct answer to complete the sentence.

guajiro [1.7K]

Explanation:

momentum increases with an increase in mass and velocity

3 0

3 years ago

The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way: OCl−+I−→OI−+Cl− T

motikmotik

Answer :

(a) The rate law for the reaction is:

$\text{Rate}=k[OCl^-]^1[I^-]^1$

(b) The value of rate constant is, $60.4M^{-1}s^{-1}$

(c) rate of the reaction is $6.52\times 10^{-5}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$OCl^-+I^-\rightarrow OI^-+Cl^-$

Rate law expression for the reaction:

$\text{Rate}=k[OCl^-]^a[I^-]^b$

where,

a = order with respect to $OCl^-$

b = order with respect to $I^-$

Expression for rate law for first observation:

$1.36\times 10^{-4}=k(1.5\times 10^{-3})^a(1.5\times 10^{-3})^b$ ....(1)

Expression for rate law for second observation:

$2.72\times 10^{-4}=k(3.0\times 10^{-3})^a(1.5\times 10^{-3})^b$ ....(2)

Expression for rate law for third observation:

$2.72\times 10^{-4}=k(1.5\times 10^{-3})^a(3.0\times 10^{-3})^b$ ....(3)

Dividing 1 from 2, we get:

$\frac{2.72\times 10^{-4}}{1.36\times 10^{-4}}=\frac{k(3.0\times 10^{-3})^a(1.5\times 10^{-3})^b}{k(1.5\times 10^{-3})^a(1.5\times 10^{-3})^b}\\\\2=2^a\\a=1$

Dividing 1 from 3, we get:

$\frac{2.72\times 10^{-4}}{1.36\times 10^{-4}}=\frac{k(1.5\times 10^{-3})^a(1.5\times 10^{-3})^b}{k(1.5\times 10^{-3})^a(3.0\times 10^{-3})^b}\\\\2=2^b\\b=1$

Thus, the rate law becomes:

$\text{Rate}=k[OCl^-]^a[I^-]^b$

a = 1 and b = 1

$\text{Rate}=k[OCl^-]^1[I^-]^1$

Now, calculating the value of 'k' (rate constant) by using any expression.

$1.36\times 10^{-4}=k(1.5\times 10^{-3})(1.5\times 10^{-3})$

$k=60.4M^{-1}s^{-1}$

Now we have to calculate the rate for a reaction when concentration of $OCl^-$ and $I^-$ is $1.8\times 10^{-3}M$ and $6.0\times 10^{-4}M$ respectively.

$\text{Rate}=k[OCl^-][I^-]$

$\text{Rate}=(60.4M^{-1}s^{-1})\times (1.8\times 10^{-3}M)(6.0\times 10^{-4}M)$

$\text{Rate}=6.52\times 10^{-5}Ms^{-1}$

Therefore, the rate of the reaction is $6.52\times 10^{-5}Ms^{-1}$

8 0

3 years ago

connection between fossil fuels, CO2, greenhouse effect and climate change? must include all 4 in answer please

natima [27]

The fossil fuels, CO2, greenhouse effect, and climate change are all things that are connected with each other and contribute for each successive one to occur. The fossil fuels are heavily used by the humans. Through their burning, the fossil fuels release lot of CO2 into the atmosphere. The CO2 is the most common greenhouse gas, thus it is a gas that manages to trap the heat into the atmosphere. So as the CO2 from the burning of the fossil fuels increases in the atmosphere, the greenhouse effect also increases. The greenhouse effect is the one that manages to keep the Earth warm, which is good, but it can also pass the limit and make the whole planet much warmer, resulting in rise of the sea levels because of the melting of the ice caps and glaciers. That will cause significant climate changes all over the globe because the sea currents will change, the atmosphere will keep more heat, and the water surface will increase.

8 0

3 years ago