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Temka [501]
3 years ago
6

14 point. Please help need this ASAP.

Chemistry
1 answer:
mezya [45]3 years ago
7 0
What are you asking
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PLEASE HELP! STAT! When aqueous solutions of cadmium chloride and sodium sulfide are mixed, a precipitate of cadmium sulfide for
Marina86 [1]

The equations are given down bellow in the picture.

8 0
3 years ago
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An unknown sample of mystery element T is analyzed. According to the data 7.42% of the element is ^6T and 92.58% is ^7T. The tru
Pepsi [2]

Answer:

\boxed{\text{6.95 u; Li}}

Explanation:

1. Atomic mass of T

To get the atomic mass of T, you calculate the weighted average of the atomic masses of the isotopes.

That is, you multiply the atomic mass of each isotope by a number representing its relative importance (e.g.., its percent of the total).

\begin{array}{ccrcr}\textbf{Atom} & \textbf{Mass/u} &\textbf{Percent} & \textbf{Calculation}& \textbf{Result/u}\\^{6}\text{T}& 6.02 & 7.42 & 6.02 \times 0.0742 & 0.45\\^{7}\text{T}& 7.02 & 92.58 & 7.02 \times 0.9258& 6.50\\& & &\text{TOTAL } = &\textbf{6.95}\\\end{array}

2. Identity of T

Lithium has an atomic mass of 6.64 u.

Element T is lithium.

 

8 0
3 years ago
How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?
Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles  

W_s = weight of the solvent in g = ?

0.452=\frac{0.348\times 1000}{W_s}

W_s=770g

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

5 0
3 years ago
What is the scientific name for the substance that is dissolving in a solution?
Goryan [66]

Answer:

The solute is the substance that is being dissolved,

Explanation:

A solution is a homogeneous mixture consisting of a solute dissolved into a solvent .

4 0
3 years ago
Read 2 more answers
Write the Henderson-Hasselbalch equation for a solution of formic acid. Calculate the quotient [HCO2]/[HCO2H] at (a) pH 3.000; (
Elena L [17]

Answer:

a. 0.182

b. 1.009

c. 1.819

Explanation:

Henderson-Hasselbach equation is:

pH = pKa + log [salt / acid]

Let's replace the formula by the given values.

a. 3 = 3.74 + log [salt / acid]

3 - 3.74 = log [salt / acid]

-0.74 = log [salt / acid]

10⁻⁰'⁷⁴ = 0.182

b. 3.744 = 3.74 + log [salt / acid]

3.744 - 3.74 = log [salt / acid]

0.004 = log [salt / acid]

10⁰'⁰⁰⁴ = 1.009

c. 4 = 3.74 + log [salt / acid]

4 - 3.74 = log [salt / acid]

0.26 = log [salt / acid]

10⁰'²⁶ = 1.819

3 0
3 years ago
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