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Rudiy27
4 years ago
8

Which step would help solve the equation?

Mathematics
1 answer:
7nadin3 [17]4 years ago
7 0
Combine like terms to solve the equation
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An airplane took 2 hours to fly 600 km against a head wind. The retrun trip with the wind took 1 and two thirds hours. Find the
Agata [3.3K]

Answer:

The speed of plane in still air is 330 kmph  

Step-by-step explanation:

Given as :

The distance cover against the wind = 600 km

The time taken against the wind = 2 hours

The distance cover with the wind = 600 km

The time taken with the wind =  ( 1 + \frac{2}{3} ) hours

                                                =  \frac{5}{3} hours

Let The speed against the wind  = x - y  kmph

The speed with the wind = x + y  kmph

where x is the speed of plane in still air

And y is the speed of wind

So , Speed = \dfrac{\texrm Distance}{\texrm Time}

Or, x - y = \frac{600}{2} = 300         ......A

And x + y = \frac{600}{\frac{5}{3} }

Or , x + y = 360                                                 .......B

From eq A and B

( x + y ) - ( x - y ) = 360 - 300

Or, 2 y = 60

∴  y = \frac{60}{2} = 30  kmph

And x = 360 - 30 = 330  kmph

Hence The speed of plane in still air is 330 kmph   Answer

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Step-by-step explanation:

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